If the direction ratio of two lines are given by l + m + n = 0, mn - 2ln + lm = 0, then the angle between the lines is
0
If (2, - 1, 3) is the foot of the perpendicular drawn from the origin to the plane, then the equation of the plane is
2x + y - 3z + 6 = 0
2x - y + 3z - 14 = 0
2x - y + 3z - 13 = 0
2x + y + 3z - 10 = 0
B.
2x - y + 3z - 14 = 0
C.
2x - y + 3z - 13 = 0
Let the equation of any plane passing through P(2, - 1, 3) is a(x - 2) + b(y + 1) + c(z - 3) = 0... (i)
Where a, b, c are the direction ratios
Since, point O (0, 0, 0) is perpendicular to the foot of the plane at a point P(2, - 1, 3).
Direction's of OP = 2, -1, 3
Since the line OP is perpendicular to the plane,therefore the direction's of the normal to the plane is proportional to the directon is of OP
Required equation of plane is
2(x - 2) - 1(y + 1)+ 3 (z - 3) = 0
2x - 3y + 3z - 14 = 0
If the plane 3x - 2y - z - 18 = 0 meets the coordinate axes in A, B, C then the centroid of is
(2, 3, - 6)
(2, - 3, 6)
(- 2, - 3, 6)
(2, - 3, - 6)
If the direction cosines of two lines are such that l + m + n = 0, l2 + m2 - n2 = 0, then the angle between them is :
The ratio in which yz-plane divides the line segment joining ( - 3, 4, - 2) and (2, 1, 3) is
- 4 : 1
3 : 2
- 2 : 3
1 :4
In a quadrilateral ABCD, the point P divides DC in the ratio 1 : 2 and Q is the mid point of AC. If then k is equal
- 6
- 4
6
4