A person observes the top of a tower from a point A on the ground. The elevation of the tower from this point is 60°. He moves 60 min the direction perpendicular to the line joining A and base of the tower. The angle of elevation of the tower from this point is 45°.Then, the height of the tower (in metres) is
The direction ratios of the two lines AB and AC are 1, - 1, - 1 and 2, - 1, 1. The direction ratios of the normal to the plane ABC are
2, 3, -1
2, 2, 1
3, 2, - 1
- 1, 2, 3
A plane passing through(- 1, 2, 3) and whose normal makes equal angles with the coordinate axes is
x + y + z + 4 = 0
x - y + z + 4 = 0
x + y + z - 4 = 0
x + y + z = 0
A variable plane passes through a fixed point (1, 2, 3). Then, the foot of the perpendicular from the origin to the plane lies on
a circle
a sphere
an ellipse
a parabola
The locus of the centroid of the triangle with vertices at (acos(θ), asin(θ)), (bsin(θ), - bcos(θ)) and (1, 0) is (here, θ is a parameter)
If (2, - 1, 2) and (K, 3, 5) are the triads of direction ratios of two lines and the angle between them is 45°, then the value of K is
2
3
4
6
The length of perpendicular from the origin to the plane which makes intercepts respectively on the coordinate axes is
5
If the plane 56x + 4y + 9z = 2016 meets the coordinate axes in A, B, C, then the centroid of the ABC is
(12, 168, 224)
(12, 168, 112)
The equation of the plane through (4,4,0) and perpendicular to the planes 2x + y + 2z + 3 = 0 and 3x + 3y + 2z - 8 = 0
4x + 3y + 3z = 28
4x - 2y - 3z = 8
4x + 2y + 3z = 24
4x +2y - 3z = 24
B.
4x - 2y - 3z = 8
(b) Equations of plane passing through (4, 4, 0) is given by a(x - 4) + b(y - 4) + c(z - 0) = 0, where a, b, c are DR's of normal to the plane
Since this plane is to the given plans, therefore,
we get
2a + b + 2c =0
and 3a + 3b + 2c = 0
By cross-multiplication method