The extreme values of 4cosx2cosπ3 +&n

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 Multiple Choice QuestionsMultiple Choice Questions

221.

If cos2x = 2 + 1cosx - 12, cosx  12 then x 

  • 2 ± π3 : n  Z

  • 2 ± π6 : n  Z

  • 2 ± π2 : n  Z

  • 2 ± π4 : n  Z


222.

In a ABCacos2B + cos2C + cosAccosC + bcosB is equal to

  • a

  • b

  • c

  • a + b + c


223.

In a ABC, b +ctanA2tanB - C2 is equal to

  • a

  • b

  • c

  • 0


224.

If cosθ - 4sin(θ) = 1, then sin(θ) + 4cosθ is equal to 

  • ± 1

  • 0

  • ± 2

  • ± 4


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225.

The extreme values of 4cosx2cosπ3 + x2cosπ3 - x2 over R, are

  • - 1, 1

  • - 2, 2

  • -3, 3

  • - 4, 4


A.

- 1, 1

Let  f x = 4cosx2cosπ3 + x2cosπ3 - x2                = 2cosx2cos2π3 + cos2x2                    2cosAcosB = cosA + B + cosA - B                = 2cosx2- 12 + cos2x2                = - cosx2 + 2cosx2cos2x2                = - cosx2 + cos3x2 + cosx2     fx = cos3x2   ...iOn differentiating w.r.t. x, we getf'x = - 3sin3x26xFor extremum, put f'x = 0 - 3sin3x26x = 0 x = 0, πPut x = 0, π in equation i, we get  f0 = cos0 = 1 fπ = cosπ = - 1


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226.

Two sides of a triangle are given by the roots of the equation x2 - 5x + 6 = 0 and the angle between the sides is π3.Then, the perimeter of

  • 5 +2

  • 5 +3

  • 5 +5

  • 5 +7


227.

A tower, of x metres high, has a flagstaff at its top. The tower and the flagstaff subtend equal angles at a point distant y metres from the foot of the tower. Then, the length of the flagstaff(in metres), is

  • yx2 - y2x2 +  y2

  • xy2 + x2y2 - x2

  • xx2 + y2x2 - y2

  • xx2 - y2x2 + y2


228.

sin120°cos150° - cos240°sin330° is equal to :

  • 1

  • - 1

  • 23

  • - 3 + 14


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229.

csc15° + sec15° is equal to :

  • 22

  • 6

  • 26

  • 6 + 2


230.

If 5cos(x) + 12cos(y) = 13, then the maximum value of 5 sin(x) + 12sin(y) is :

  • 12

  • 120

  • 20

  • 13


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