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Trigonometric Functions

Multiple Choice Questions

301.

$If (1 + \tan (α)) (1 + \tan (4 α)) = 2, α \in (0, \frac{π}{16}), then α = ?$

$\frac{π}{20}$
$\frac{π}{30}$
$\frac{π}{40}$
$\frac{π}{50}$

302.

$If \cos (θ) = \frac{\cos (α) - \cos (β)}{1 - \cos (α) \cos (β)}, then one of the values of \tan (\frac{θ}{2}) is$

$\cot (\frac{β}{2}) \tan (\frac{α}{2})$
$\tan (\frac{α}{2}) \tan (\frac{β}{2})$
$\tan (\frac{β}{2}) \cot (\frac{α}{2})$
$\tan^{2} (\frac{α}{2}) \tan^{2} (\frac{β}{2})$

303.

The value of the expression $\frac{1 + \sin (2 α)}{\cos (2 α - 2 π) \tan (α - \frac{3 π}{4})} - \frac{1}{4} \sin (2 α) [\cot (\frac{α}{2}) + \cot (\frac{3 π}{2} + \frac{α}{2})] is$

0
1
$\sin^{2} (\frac{α}{2})$
$\sin^{2} (α)$

304.

$If \frac{1}{6} \sin (θ), \cos (θ) and \tan (θ) are in geometric progression, then the solution set of θ is$

$2 nπ \pm (\frac{π}{6})$
$2 nπ \pm (\frac{π}{3})$
$nπ + {(- 1)}^{n} (\frac{π}{3})$
$nπ + (\frac{π}{3})$

305.

$In ∆ ABC if x = \tan (\frac{B - C}{2}) \tan (\frac{A}{2}), y = \tan (\frac{C - A}{2}) \tan (\frac{B}{2}) and z = \tan (\frac{A - B}{2}) \tan (\frac{C}{2}), then (x + y + z) = ?$

xyz
- xyz
2xyz
$\frac{1}{2} xyz$

306.

$If A > 0, B > 0 and A + B = \frac{π}{3}, then the maximum value of Atan (B) is$

$\frac{1}{\sqrt{3}}$
$\frac{1}{3}$
$\frac{1}{2}$
$\sqrt{3}$

307.
$In ∆ ABC, if bcos (θ) = c - a, (where θ is an acute angle), then (c - a) \tan (θ) = ?$

$2 \sqrt{ca} \cos (\frac{B}{2})$

$2 \sqrt{ac} \sin (\frac{B}{2})$

$2 cacos (\frac{B}{2})$

$2casin (\frac{B}{2})$

$2 \sqrt{ac} \sin (\frac{B}{2})$

$(b) We have, In ∆ ABC, if \cos (θ) = \frac{c - a}{b} \sin (θ) = \sqrt{1 - \cos^{2} (θ)} = \sqrt{1 - \frac{{(c - a)}^{2}}{b^{2}}} = \frac{\sqrt{b^{2} - {(c - a)}^{2}}}{b} Now, \tan (θ) = \frac{\sqrt{b^{2} - {(c - a)}^{2}}}{(c - a)} \Rightarrow (c - a) \tan (θ) = \sqrt{b^{2} - {(c - a)}^{2}} = \sqrt{b^{2} - c^{2} - a^{2} + 2 ac} = \sqrt{2 ac - 2 accos (B)} [Using cosine rule] = \sqrt{2 ac} \sqrt{1 - \cos (B)} = \sqrt{2} \sqrt{ac} \sqrt{2 \sin^{2} (\frac{B}{2})} = 2 \sqrt{ac} \sqrt{\sin^{2} (\frac{B}{2})} = 2 \sqrt{ac} \sin (\frac{B}{2})$

308.

$If \tan (α) and \tan (β) are the roots of the equation x^{2} + px + q = 0, then the value of \sin^{2} (α + β) + pcos (α + β) \sin (α + β) + {qcos}^{2} (α + β)$