A girl walks 4 km towards West, then she walks 3 km in a drection 30° East of North and stops. Then, the girl's displacement from herinitial point of departures is
None of these
A.
Let O and B be the initial and final poitions of the girl, respectively.
Then, the girl's position can be shown as in the figure
(AB cos(60°) is component of AB along X-axis and AB sin(60°) is component of AB along Y-axis).
By the triangle law of vector addition, we have
OB = AO + AB
Hence, the girl's displacement from her initial point of departure is .
If a = ,b = and c = are linearly dependent vectors and , then the value of are respectively
None of these
Forces of magnitude 5 and 3 units acting in the directions and respectively act on a particle which is displaced from the point (2, 2, - 1) to (4, 3, 1). The work done by the forces is
148 units
None of these
The points, whose position vectors are 60i + 3j, 40i - 8j and ai - 52j collinear, if
a = 40
a = - 40
a = 20
a = - 20
If a = i - j + k, a b = 0, a x b = c, where c = - 2i - j + k, then b 1s equal to
(1, 0, - 1)
(0, 1, 1)
(- 1, - 1, 0)
(- 1, 0, 1)
The resultant of P and Q is R. If Q is doubled, R is also doubled and if Q is reversed, R is again doubled. Then, P2 : Q2 : R2 gven by
2 2 3
3 2 2
2 3 2
2 3 1
Forces ofmagnitudes 3, P, 5, 10 and Q are respectively acting along the sides AB, BC, CD, AD and the diagonal CA of a rectangle ABCD, where AB = 4m and BC = 3m. Ifthe resultant is a single force along the other diagonal BD, then P, Q and the resultant are
5, 6, 7
None of the above