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 Multiple Choice QuestionsMultiple Choice Questions

221.

A girl walks 4 km towards West, then she walks 3 km in a drection 30° East of North and stops. Then, the girl's displacement from herinitial point of departures is

  • - 52i^ + 332j^

  • 12i^ + 32j^

  • - 12i^ + 332j^

  • None of these


222.

If a = i^ + j^ + k^,b = 4i^ + 3j^ + 4k^ and c = i^ + αj^ + βk^ are linearly dependent vectors and c = 3, then the value of α and β are respectively

  • ± 1, 1

  • ± 2, 1

  • 0, ± 1

  • None of these


223.

The projection of the vector a = i^ - 2j^ + k^ on  the vextor b = 4i^ - 4j^ + 7k^ is

  • 919

  • 199

  • 9

  • 19


224.

Forces of magnitude 5 and 3 units acting in the directions 6i^ + 2j^ +3k^ and 3i^ - 2j^ +6k^ respectively act on a particle which is displaced from the point (2, 2, - 1) to (4, 3, 1). The work done by the forces is

  • 148 units

  • 1487 units

  • 787 units

  • None of these


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225.

If a and b are unit vectors and θ is the angle between them, then la + bl < 1, if

  • θ = π2

  • θ < π3

  • π  θ > 2π3

  • π3 < θ < 2π3


226.

The points, whose position vectors are 60i + 3j, 40i - 8j and ai - 52j collinear, if

  • a = 40

  • a = - 40

  • a = 20

  • a = - 20


227.

In a ABC, AB = ri + j, AC = si - j if the area of triangle is of unit magnitude, then

  • r - s = 2

  • r + s = 1

  • r + s = 2

  • r - s = 1


228.

If a = i - j + k, a b = 0, a x b = c, where c = - 2i - j + k, then b 1s equal to

  • (1, 0, - 1)

  • (0, 1, 1)

  • (- 1, - 1, 0)

  • (- 1, 0, 1)


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229.

The resultant of P and Q is R. If Q is doubled, R is also doubled and if Q is reversed, R is again doubled. Then, P2 : Q2 : R2 gven by

  • 2 2 3

  • 3 2 2

  • 2 3 2

  • 2 3 1


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230.

Forces ofmagnitudes 3, P, 5, 10 and Q are respectively acting along the sides AB, BC, CD, AD and the diagonal CA of a rectangle ABCD, where AB = 4m and BC = 3m. Ifthe resultant is a single force along the other diagonal BD, then P, Q and the resultant are

  • 4, 10512, 121112

  • 5, 6, 7

  • 312, 8, 912

  • None of the above


A.

4, 10512, 121112

ABCD is a rectangle in which AB = 4m and BC =3m

Then, tanθ = BCAB = 34

The forces 3, P, 5, 10 and Q newtons have the resultant R Newton as shown in the figure.

Rcosθ = Qcosθ + 5 - 3             = Qcosθ + 2                   ...iand Rsinθ = P + 10 - Qsinθ   ...iiand Q ABsinθ + 5BC = 10 . AB        sinθ = 35 and cosθ = 45 125Q = 40 - 15 = 25      Q = 12512 = 10512 newtonThen, find R from Eq. (i) and P from Eq. (ii)    4R5 = 12512 × 45 + 2 4R = 1253 + 10 = 1553   R = 15512 = 121112and 15512 × 35 = P + 10 - 12512 × 35           1554 = 5P + 50 - 1254              5P = 1554 + 1254 - 50             5P = 2804 - 50 = 70 - 50 = 20               P = 4Hence, option (a) 4, 10512, 121112 is correct.


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