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 Multiple Choice QuestionsMultiple Choice Questions

391.

If a = i^ - 2j^5 and b = 2i^ + j^ + 3k^14 are vectors in space, then the value of 2a +b . a × b × a - 2b is

  • 0

  • 1

  • 5

  • 4


392.

The value of i^ . j^ × k^ + j^ . k^ × i^ + k^ . i^ × j^ is

  • 0

  • 1

  • 3

  • - 3


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393.

The values of λ, such that (x, y, z) if (0, 0, 0) and i^ + j^ + 3k^x + 3i^ - 3j^ + k^y + - 4i^ + 5j^ are

  • 0, 1

  • - 1, 1

  • - 1, 0

  • - 2, 0


C.

- 1, 0

Given, i^ + j^ + 3k^x + 3i^ - 3j^ + k^y + - 4i^ + 5j^z = λi^x + j^y + k^zOn equating the coefficients of i^, j^ and k^ both sides, we have     x +3y - 4z = λx     x - 3y + 5z = λyand 3x + y + 0 = λzAbove three equations can be rewritten as1 - λx + 3y - 4z = 0  x - 3 + λy + 5z = 0            3x + y - λz = 0

This is homogeneous system of equations in three vanables x, y and z.

It is consistent and have non-zero solution

i.e., (x, y, z) (0, 0, 0), If determinant of coefficient matrix is zero.

 1 - λ3- 41- 3 + λ531- λ = 0On expanding along first row, we have1 - λλ3 + λ - 5 - 3- λ - 15 - 41 + 9 + 3λ = 0 1 - λλ2 + 3λ - 5 + 3λ + 45 - 40 - 12λ = 0         λ2 + 3λ - 5 - λ3 - 3λ2 + 5λ - 9λ + 5 = 0 - λ3 - 2λ2 - λ = 0   λλ2 + 2λ + 1 = 0            λλ + 12 = 0                         λ = 0, - 1


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394.

If G and G' are respectively centroid of ABC and A' B' C', then AA' + BB' + CC' is equal to

  • 2GG'

  • 3GG'

  • 23GG'

  • 13GG'


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395.

If a = 3i^ - 4j^ + 5k^, b = i^ + j^ + k^ and c = - 2i^ + 3j^ - 5k^, and if [·] is the least integer function, then [a + b + c] is equal to

  • 1

  • 2

  • 3

  • 0


396.

If a = - i^ + j^ + k^ and b = 2i^ + k^, then the vector satisfyin the following conditions

(i) it is coplanar witha and b,

(ii) it is perpendicular to b and

(iii) a · c = 7, is

  • - i^ + 2j^ + 2k^

  • - 32i^ + 52j^ + 3k^

  • - 3i^ + 5j^ + 6k^

  • - 6i^ + k^


397.

If the vectors b = tanα, - 1, 2sinα2 and c = tanα, tanα,  - 3sinα2 are orthagonal and  a vector a = 1, 3, sin2α makes an obtuse angle with the Z-axis, then the value of α is

  • 4n + 2π + tan-12

  • 4n + 2π - tan-12

  • 4n + 1π + tan-12

  • 4n + 1π - tan-12


398.

r . i^2 + r . j^2 + r . k^2 is equal to

  • 0

  • 1

  • r2

  • 3r2


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399.

The component of i^ + j^ along j^ and k^ will be

  • i^ + j^2

  • j^ + k^2

  • k^ + i^2

  • None of these


400.

If a = 2i^ + 5j^ and b = 2i^ - j^, then the unit vector along a + b will be

  • i^ - j^2

  • i^ + j^

  • 2i^ + j^

  • i^ + j^2


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