What is the energy of the electron revolving in third orbit expressed in eV ?
1.51 eV
3.4 eV
4.53 eV
4 eV
An α -particle of energy 5 MeV is scattered through 180° by gold nucleus. The distance of closest approach is of the order of
10-14 cm
10-10 cm
10-16 cm
10-12 cm
Find the de-Broglie wavelength of an electron with kinetic energy of 120 eV.
112 pm
95 pm
124 pm
102 pm
A.
112 pm
Given, E = 120 eV
We know that de-Broghe wavelength of an electron,
What is the wavelength of light for the least energetic photon emitted in the Lyman series of the hydrogen spectrum ? (take, hc = 1240 eV nm)
122 nm
82 nm
150 nm
102 nm
If an electron in hydrogen atom jumps from an orbit of level n = 3 to an orbit oflevel n =2, the emitted radiation has a frequency (R = Rydberg constant, c = velocity of light)
The de-Broglie wavelength of an electron accelerated to a potential of 400 V is approximately
0.03 nm
0.04 nm
0.12 nm
0.06 nm
Total energy of electron in an excited state of hydrogen atom is − 3.4 eV. The kinetic and potential energy of electron in this state are
K = − 3.4 eV, U = − 6.8 eV
K = 3.4 eV, U − 6.8 eV
K = − 6.8 eV, U = + 3.4 eV
K = + 10.2 eV, U = − 13.6 eV
When electron jumps from n = 4 level to n = 1 level, the angular momentum of electron changes by
A particle is dropped from a height H. The de-Broglie wavelength of the particle depends on height as
H-1/2
H0
H1/2
H
The energy (in eV) required to excite an electron from n = 2 to n = 4 state in hydrogen atom is
− 0.85
+ 4.25
− 3.4
+ 2.55