In the spectrum of hydrogen, the ratio of the longest wavelength

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 Multiple Choice QuestionsMultiple Choice Questions

101.

Hydrogen atom in ground state is excited by a monochromatic radiation of straight lambda space equals space 975 space straight A with straight o on top. The number of spectral lines in the resulting spectrum emitted will be,

  • 3

  • 2

  • 6

  • 6

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102.

The wavelength λe of an electron and λp of a photon of same energy E are related by

  • straight lambda subscript straight p proportional to space straight lambda subscript straight e superscript 2
  • straight lambda subscript straight p proportional to space straight lambda subscript straight e
  • straight lambda subscript straight p proportional to square root of space straight lambda subscript straight e end root
  • straight lambda subscript straight p proportional to square root of space straight lambda subscript straight e end root
1378 Views

103.

A certain mass of hydrogen is changed to helium the process of fusion. The mass defect in fusion reaction is 0.02866 u. The energy liberated per u is (given 1 u =931 MeV)

  • 2.67 MeV

  • 26.7 MeV

  • 6.675 MeV

  • 6.675 MeV

2120 Views

104.

Ratio of longest wavelength corresponding to Lyman and Balmer series in hydrogen spectrum is 

  • 5/27

  • 3/23

  • 7/29

  • 7/29

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105.

Electrons used in an electron microscope are accelerated by a voltage of 25 kV. If the voltage is increased to 100 kV then the de - Broglie wavelength associated with the electrons would

  • decrease by 2 times

  • decrease by 4 times

  • increase by 4 times

  • increase by 4 times

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106.

The wavelength of the first line of Layman series for the hydrogen atom is equal to that of the second line of Balmer series for a hydrogen-like an ion. The atomic number Z  of hydrogen-like ion is 

  • 4

  • 1

  • 2

  • 2

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107.

In the spectrum of hydrogen, the ratio of the longest wavelength in the Lyman series to the longest wavelength in the Balmer series is 

  • 4/9

  • 9/4

  • 27/5

  • 27/5


D.

27/5

In hydrogen atom, wavelength of characteristic spectrum


1 over straight lambda space equals space Rz squared open square brackets fraction numerator 1 over denominator straight n subscript 1 superscript 2 end fraction minus fraction numerator 1 over denominator straight n subscript 2 superscript 2 end fraction close square brackets

For space layman space series space straight n subscript 1 space equals space 1 comma space straight n subscript 2 space equals space 2
1 over straight lambda subscript 1 space equals space Rz squared open square brackets 1 over 1 squared minus 1 over 2 squared close square brackets space space... space left parenthesis straight i right parenthesis space

For space Balmer space series space straight n subscript 1 space equals space 2 comma space straight n subscript 2 space equals space 3

1 over straight lambda subscript 2 space equals space Rz squared open square brackets 1 over 2 squared minus 1 over 3 squared close square brackets space space... space left parenthesis ii right parenthesis space

Dividing space eq space left parenthesis ii right parenthesis space by space eq space left parenthesis straight i right parenthesis space space we space get
straight lambda subscript 1 over straight lambda subscript 2 space equals space fraction numerator Rz squared open square brackets 1 fourth minus 1 over 9 close square brackets space over denominator Rz squared open square brackets 1 over 1 minus 1 fourth close square brackets space end fraction equals fraction numerator begin display style 5 over 36 end style over denominator begin display style 3 over 4 end style end fraction
straight lambda subscript 1 over straight lambda subscript 2 space equals space 5 over 36 straight x space 4 over 3 space equals space 5 over 27

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108.

The energy of a hydrogen atom in the ground state is -13.6 eV. The energy of a He+ ion in the first excited state will be

  • -13.6 eV

  • -27.2 eV

  • -54.4eV

  • -54.4eV

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109.

The potential difference that must be applied to stop the fastest photoelectrons emitted by a nickel surface, having work function 5.01 eV, when ultraviolet light of 200 nm falls on it, must be

  • 2.4 V

  • -1.2 V

  • -2.4 V

  • -2.4 V

1339 Views

110.

The electron in the hydrogen atom jumps from excited state (n=3) to its ground state (n=1) and the photons thus emitted irradiate a photosensitive material. If the work functions of the material is 5.1 eV, the stopping potential is estimated to be (the energy of the electron is nth state En = -13.6/n2 eV)

  • 5.1 V

  • 12.1 V

  • 17.2 V

  • 17.2 V

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