In a photoelectric effect measurement, the stopping potential for a given metal is found to be V volt when radiation ofwavelength λ0 is used. If radiation of wavelength 2λ0 is used with the same metal then the stopping potential (in volt) will be
2V0
The wavelength of a 1 keV photon is 1.24 nm. The frequency of 1 MeV photon is
1.24 × 1015 Hz
2.4 × 1020 Hz
1.24 × 1018 Hz
2.4 × 1024 Hz
A photon of energy 8 eV is incident on metal surface of threshold frequency 1.6 x 1015 Hz. The kinetic energy of the photoelectrons emitted (in eV) : (Take h = 6 x 10-34 J-s)
1.6
6
2
1.2
If the wavelength of incident light changes from 400 nm to 300 nm, the stopping potential for photoelectrons emitted from a surface becomes approximately
1.0 V greater
1.0 V smaller
0.5 V greater
0.5 V smaller
A radio transmitter radiates 1 kW power at a wavelength 198.6 m. How many photons does it emit per second ?
1010
1020
1030
1040
C.
1030
If the speed of light were 2/3 of its present value, the energy released in a given atomic explosion would
decrease by a factor 2/3
decrease by a factor 4/9
decrease by a factor 5/9
decrease by a factor
The rate of emission of a black body at 0°C is R, its rate of emission at 273°C is
4 R
8 R
16 R
32 R
There are n1 photons of frequency v1 in a beam oflight. In an equally energetic beam there are n2 photons of frequency v2. Then the correct relation
In photoelectric effect, the number of electrons ejected per second is
proportional to the wavelength of light
proportional to the intensity of light
proportional to the work function of the metal
proportional to the frequency of light