Using mass (M), length (L), time (T ) and current (A) as fun

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 Multiple Choice QuestionsMultiple Choice Questions

151.

In a case of infinite long wire electric field is proportional to

  • 1r

  • 1r2

  • 1r3

  • r0


152.

Assertion: In a cavity within a conductor, the electric field is zero.

Reason: Charges in a conductor reside only at its surface.

  • If both assertion and reason are true and reason is the correct explanation of assertion

  • If both assertion and reason are true but reason is not the correct explanation of assertion

  • If assertion is true but reason is false

  • If both assertion and reason are false


153.

Two parallel large thin metal sheets have equal surface charge densities ( σ = 26.4 × 10-12 C/m2 ) of opposite signs. The electric field between these sheets is

  • 1.5 N/C

  • 1.5 × 10-10 N/C

  • 3 N/C

  • 3 × 10-10 N/C 


154.

The spatial distribution of the electric field due to two charges (A, B) is shown in figure. Which one of the following statements is correct?

  • A is +ve and +B is -ve and A > B

  • A is -ve and B is +ve; A = B

  • both are +ve but A > B

  • both are -ve but A > B


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155.

Using mass (M), length (L), time (T ) and current (A) as fundamental quantities, the dimension of permeability is

  • [ M-1 L T-2 A ]

  • [ M L2 T-2 A-1 ]

  • [ M L T-2A-2 ]

  • [ M L T-1 A-1 ]


C.

[ M L T-2A-2 ]

We know that the force per unit length of a wire carrying current due to another parallel wire increase of temperature. Which in turn implies that carrying current is given by

   dFdt  =  μoi1i22πd

⇒  μo2πdi1 i2 dFdl

   [ μo ] = LA2 · M L T-2 L

    [ μo ] = [ M L T-2 ] [A-2 ]


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156.

Length cannot be measure by

  • fermi

  • micron

  • debye

  • light year


157.

Two spheres of same metal have radii a and b. Thet have been connected to a conducting wire. Find the ratio of the electric field intensity upon them.

  • a/b

  • b/a

  • b2 / a

  • b2/a2


158.

Figure shows the electric lines of forces emerging from a charged body. If the electric field at A and B are EA and  EB respectively and if the displacement between A and B is r, then

    

  • EA > EB

  • EA < EB

  • EA = EB/r

  • EA = E/ r2


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159.

Qεo

  • Q6εo

  • Q6 εo

  • Qεo a2

  • Q4πεoa2


160.

A small piece of metal wire is dragged across the gap between the pole pieces of a magnet in 0.4 sec. If magnetic flux between the pole pieces is known to be 8 × 10-4 Wb, then induced emf in the wire, is

  • 4 × 10-3 V

  • 8 × 10-3 V 

  • 20 × 10-3 V

  • 6 × 10-3 V


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