The radius of orbit of a planet is two times that of the earth. T

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 Multiple Choice QuestionsMultiple Choice Questions

181.

In an earth's satellite, the astronaut stands on a platform. His weight as indicated by the balance will be

  • 6g

  • 2g

  • 8g

  • zero


182.

A body of mass m is moved to a height h equal to the radius of the earth. The increase in potential energy is

  • 2mgR

  • mgR

  • 12mgR

  • 14mgR


183.

Escape velocity from a planet is v, If its mass is increased to 8 times and its radius is increased to 2 times, then the new escape velocity would be :

  • ve

  • 2ve

  • 2ve

  • 22ve


184.

Acceleration due to gravity:

  • decreases from the equator to poles

  • decreases from poles to the equator

  • is maximum at the centre of the earth

  • is maximum at the equator


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185.

The distance between the sun and the earth be r then the angular momentum of the earth around the sun is proportional to :

  • r

  • r3/2

  • r

  • none of these


186.

The length of the second's pendulum is 1 m on earth. If the mass and diameter of a planet are doubled than that of earth. Then its length becomes

  • 1 m

  • 2 m

  • 0.5 m

  • 4 m


187.

Two satellites A and B go around a planet P in circular orbits having radius 4 R and R respectively. If the speed of satellite A is 3v, then the speed of satellite B will be

  • 6v

  • 9v

  • 3v

  • none of these


188.

The period of oscillation of a simple pendulum of constant length at the surface of the earth is T. Its time period inside a mine will be :

  • can not be compared

  • equal to T

  • less than T

  • more than T


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189.

The radius of orbit of satellite of earth is R. Its kinetic energy is proportional to :

  • 1R

  • 1R

  • R

  • 1R3/2


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190.

The radius of orbit of a planet is two times that of the earth. The time period of the planet is :

  • 4.2 T

  • 2.8 T

  • 5.6 T

  • 8.4 T


B.

2.8 T

Applying Kepler's law

T2 ∝ R3

Hence, T1T22 = R1R23 = R2R3TT2 = 123/2T2 = (2)3/2TT2 = 2.8T


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