A body when fully immersed in a liquid of specific gravity 1.2 weighs 44 gwt. The same body when fully immersed in water weighs 50 gwt. The mass of the body is

• 36 g

• 48 g

• 64 g

• 80 g

The wettability of a surface by a liquid depends primarily on

• viscosity

• surface tension

• density

• angle of contact between the surface and the liquid

In the given (V-T) diagram, what is the relation between pressures p₁ and p₂ ?

• p₂ = p₁

• p₂ > p₁

• p₂ < p₁

• Cannot be predicted

A small metal sphere of radius a is falling with a velocity v through a vertical column of a viscous liquid. If the coefficient of viscosity of the liquid is η, then the sphere encounters an opposing force of

• $6{\mathrm{\pi \eta a}}^2\mathrm{v}$

• $\frac{6\mathrm{\eta v}}{\mathrm{\pi a}}$

• $6\mathrm{\pi \eta av}$

• $\frac{\mathrm{\pi \eta v}}{6{\mathrm{a}}^3}$

A drop of some liquid of volume 0.04 cm³ is placed on the surface of a glass slide. Then another glass slide is placed on it in such a way that the liquid forms a thin layer of area 20 cm² between the surfaces of the two slides. To separate the slides a force of 16 x10⁵ dyne has to be applied normal to the surfaces. The surface tension of the liquid is (in dyne-cm^-1)

• 60

• 70

• 80

• 90

To determine the composition of a bimetallic alloy, a sample is first weight in air and then in water. These weights are found to be w₁ and w₂ respectively. If the densities of the two constituents metals are ρ₁ and ρ₂ respectively, then the weight of the first metal in the sample is (where ρ_w is the density of water)

• $\frac{{\mathrm{\rho }}_1}{{\mathrm{\rho }}_{\mathrm{w}} \left({\mathrm{\rho }}_2 - {\mathrm{\rho }}_1\right)} \left[{\mathrm{w}}_1 \left({\mathrm{\rho }}_2 - {\mathrm{\rho }}_{\mathrm{w}}\right) - {\mathrm{w}}_2{\mathrm{\rho }}_2\right]$

• $\frac{{\mathrm{\rho }}_1}{{\mathrm{\rho }}_{\mathrm{w}} \left({\mathrm{\rho }}_2 + {\mathrm{\rho }}_1\right)} \left[{\mathrm{w}}_1 \left({\mathrm{\rho }}_2 - {\mathrm{\rho }}_{\mathrm{w}}\right) + {\mathrm{w}}_2{\mathrm{\rho }}_2\right]$

• $\frac{{\mathrm{\rho }}_1}{{\mathrm{\rho }}_{\mathrm{w}} \left({\mathrm{\rho }}_2 - {\mathrm{\rho }}_1\right)} \left[{\mathrm{w}}_1 \left({\mathrm{\rho }}_2 + {\mathrm{\rho }}_{\mathrm{w}}\right) - {\mathrm{w}}_2{\mathrm{\rho }}_1\right]$

• $\frac{{\mathrm{\rho }}_1}{{\mathrm{\rho }}_{\mathrm{w}} \left({\mathrm{\rho }}_2 - {\mathrm{\rho }}_1\right)} \left[{\mathrm{w}}_1 \left({\mathrm{\rho }}_1 - {\mathrm{\rho }}_{\mathrm{w}}\right) - {\mathrm{w}}_2{\mathrm{\rho }}_1\right]$

A 20 cm long capillary tube is dipped vertically in water and the liquid rises upto 10 cm. If the entire system is kept in a freely falling platform, the length of the water column in the tube will be

• 5 cm

• 10 cm

• 15 cm

• 20 cm