The power radiated by a black body is P and it radiates maximum e

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 Multiple Choice QuestionsMultiple Choice Questions

101.

A black body is at 727o C. It emits energy at a rate which is proportional to:

  • (727)2

  • (1000)4

  • (1000)2

  • (1000)2

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102.

An engine has an efficiency of 1/6. When the temperature of sink is reduced by 62o C, its efficiency is doubled. The temperature of the source is:

  • 124o C

  • 37o C

  • 62o C

  • 62o C

2481 Views

103.

A black body at 1227°C emits radiations with maximum intensity at a wavelength of 5000 Å. If the temperature of the body is increased by 1000°C, the maximum intensity will be observed at

  • 4000 Å

  • 5000 Å

  • 6000 Å

  • 6000 Å

820 Views

104.

A gas mixture consists of 2 moles of O2 and 4 moles of Ar at temperature T. Neglecting all vibrational modes, the total internal energy of the system is

  • 4 RT

  • 15 RT

  • 9 RT

  • 9 RT

1367 Views

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105.

The de-Broglie wavelength of a neutron in thermal equilibrium with heavy water at a temperature T (Kelvin) and mass m, is

  • fraction numerator straight h over denominator square root of mKT end fraction
  • fraction numerator straight h over denominator square root of 3 mKT end root end fraction
  • fraction numerator 2 straight h over denominator square root of 3 mKT end root end fraction
  • fraction numerator 2 straight h over denominator square root of 3 mKT end root end fraction
1883 Views

106.

A spherical black body with a radius of 12 cm radiates 450-watt power at 500 K. If the radius were halved and the temperature doubled, the power
radiated in watt would be

  • 225

  • 450

  • 1800

  • 1800

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107.

The power radiated by a black body is P and it radiates maximum energy at wavelength, λ0. If the temperature of the black body is now changed so that it radiates maximum energy at wavelength 34λ0, the power radiated by it becomes nP. The value of n is

  • 3/4

  • 4/3

  • 81/256

  • 256/81


D.

256/81

Apply Wien's law

λmax T = constanti.e., λmax1 T1 =  λmax2 T2 λ0T = 3λ04T'T' = 43TPower radiated P T4So, P2P1 = n = T'T4 = 434 = 25681


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108.

At what temperature will the rms speed of oxygen molecules become just sufficient for escaping from the Earth's atmosphere?

(Given: Mass of oxygen molecule (m) = 2.76 x 10-26 kg
Boltzmann's constant kB = 1.38 x 10-23 JK-1)

  • 2.508 × 104 K

  • 8.360 × 104 K

  • 1.254 × 104 K

  • 5.016 × 104 K


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109.

A piece of blue glass heated to a high temperature and a piece of red glass at room temperature are taken inside a dimly-lit room. Then,

  • The blue piece will look blue and the red piece will look red as usual.

  • the red piece will look brighter red and the blue piece will look ordinary blue.

  • the blue will look brighter as compared to the red piece.

  • Both the pieces will look equal red.


110.

A cup of tea cools from 80°C to 60°C in one minute. The ambient temperature is 30°C. In cooling from 60°C to 50°C. It will take

  • 50 sec

  • 90 sec

  • 60 sec

  • 48 sec


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