When an unpolarized light of intensity I₀ is incident on a polarizing sheet, the intensity of the light which does not get transmitted is

• I₀ /2

• I₀ /4

• zero

• zero

Unpolarized light of intensity I passes through an ideal polarizer A. Another identical polarizer B is placed behind A. The intensity of light beyond B is found to be I/2.Now another identical polarizer C is placed between A and B. The intensity beyond B is now found to be I/8. The angle between polarizer A and C is :

• 60°

• 0°

• 30°

• 45°

23.

In Young's double slits experiment, if the separation between the slits is halved, and the distance between the slits and the screen is doubled, then the fringe width compared to the original one will be

• Unchanged

• Halved

• Doubled

• Quadrupled

Huygens' wave theory of light cannot explain

• Diffraction phenomena

• Interference  phenomena 

• Photoelectric effect

• Polarization of light

For a diffraction from a single slit, the intensity of the central point is

• infinite

• finite and same magnitude as the surrounding maxima

• finite but much larger than the surrounding maxima

• finite and substantially smaller than the surrounding maxima

If a ray of light is incident at a glass surface at the Brewster's angle of 60°, then the angle of deviation inside glass is

• 90°

• 60°

• 45°

• 30°

The polarising angle for a medium is found to be 60°. The critical angle of the medium is

• ${\sin }^{-1} \left(\frac{1}{2}\right)$

• ${\sin }^{-1} \left(\frac{\sqrt{3}}{2}\right)$

• ${\sin }^{-1} \left(\frac{1}{\sqrt{3}}\right)$

• ${\sin }^{-1} \left(\frac{1}{4}\right)$

In Young's double slit experiment, to increase the fringe width

• the wavelength of the source is increased

• the source is moved towards the slit

• the source is moved away from the slit

• the slit separation is increased

Light of wavelength 5000 $\stackrel{\circ }{\mathrm{A}}$ is incident normally on a slit of width 2.5 x 10^-4 cm. The angular position of second minimum from the central maximum is

• ${\sin }^{-1} \left(\frac{1}{5}\right)$

• ${\sin }^{-1} \left(\frac{2}{5}\right)$

• $\left(\frac{\mathrm{\pi }}{3}\right)$

• $\left(\frac{\mathrm{\pi }}{6}\right)$

If the intensity ratio of two coherent sources used in Young's double slit experiment is 49 : 1, then the ratio between the maximum and minimum intensities in the interference pattern is

• 1 : 9

• 9 : 16

• 16 : 9

• 16 : 25