Two springs of force constants k and 2k are connected to a mass a

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191.

Assertion:  Sound waves cannot travel in vacuum but light can travel in vacuum. 

Reason: Sound waves are longitudinal waves and they cannot be polarised but  electromagnetic waves are transverse and they can be polarised.

  • If both assertion and reason are true and reason is the correct explanation of assertion

  • If both assertion and reason are true but reason is not the correct explanation of assertion

  • If assertion is true but reason is false

  • If both assertion and reason are false


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A stone thrown into still water, creates a circular wave pattern moving radially outwards. Ifr is the distance measured from the centre of the pattern, the amplitude of the wave varies as

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194.

When a guitar string is sounded with a 440 Hz tuning fork, a beat frequency of 5 Hz is heard. If the experiment is repeated with a tuning fork of 437 Hz, the beat frequency is 8 Hz. The string frequency (Hz) is

  • 445

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  • 429

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195.

For a wave propagating in a medium, identify the property that is independent of the others.

  • Velocity

  • Wavelength

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  • All these depend on each other


196.

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197.

Two springs are connected to a block mass M placed on a frictionless surface as shown in figure. If both the springs have a spring constant k, the frequency of oscillation of the block is


198.

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  • 14

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199.

The Magnetic Resonance Imaging (MRI) is based on the phenomenon of

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200.

Two springs of force constants k and 2k are connected to a mass as shown in figure . The frequency of oscillation of the mass is

          

  • 12πkm

  • 12π2km

  • 12π3km

  • 12πmk


C.

12π3km

Ket the mass m be displaced towards right  by a distance x. 

  

Then the spring 1 will be extended and the spring 2 will be compressed by an amount of x each.

The restoring force on mass m due to spring 1 is

    F1-kx

And the restoring force due to spring 2 is

  F2 =  - (2k) x

∴  And the restoring force due to spring 2 is

  F = F1 + F2

     = - kx - 2kx

 F = - 3kx

⇒  m d2xdt2  = - 3kx

⇒   d2xdt2 + 3kmx =  0

⇒   d2xdt2 + ω2x = 0 

where  ω23km

           ω = 3km

⇒   f = ω2π

⇒   f =  12π 3km


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