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 Multiple Choice QuestionsMultiple Choice Questions

31.

If sinβ  is  the  harmonic  mean  of sinα  and cos(α), and sin(θ) is the arithmetic mean of sinα and cosα, then which of the following is/are correct

1. 2sinα + π4sinβ = sin2α2. 2sinθ = cosα - π4Select the correct answer using the code given below :

  • 1 only

  • 2 only

  • both 1 and 2

  • neither 1 or 2 


32.

If xi > 0, yi > 0 (i = 1, 2, 3, ...... n) are the values oftwo variables X and Y with geometric means P and Q respectively, then the geometric mean of XY is

  • PQ

  • antilogPQ

  • nlogP - logQ

  • nlogP +logQ


33.

Three-digit numbers are formed from the digits 1, 2 and 3 in  such a way that the digits are ot repeated. What is the sum of such three-digit numbers ?

  • 1233

  • 1322

  • 1323

  • 1332


34.

What is the sum of the serie 0.3 + 0.33 + 0.333 +... n terms 

  • 13n - 191 - 110n

  • 13n - 291 - 110n

  • 13n - 131 - 110n

  • 13n - 191 + 110n


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35.

If the sum of m terms of an AP is n and the sum of n terms is m, then the sum of (m + n) terms is

  • mn

  • m + n

  • 2(m + n)

  • - (m + n)


36.

The sum of the roots of the equation x2 + bx + c = 0 (where b and c are non-zero) is equal to the sum of the  reciprocals of their squares. Then 1c, b, cb are in

  • AP

  • GP

  • HP

  • None of the above


37.

The sum of the roots of the equation ax2 + x + c = 0 (where a and c are non-zero) is equal to the sum of the reciprocals of their squares. Then a, ca2, c2 are in

  • AP

  • GP

  • HP

  • None of the above


38.

The fifth term of an AP of 11 terms, whose sum is n2 - 2n, is

  • 5

  • 7

  • 8

  • 15


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39.

The sum of all the two-digit odd numbers is

  • 2475

  • 2530

  • 4905

  • 5049


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40.

The sum of the first n terms of the series 12 + 34 + 78 + 1516 + ... = ?

  • 2n - n - 1

  • 1 - 2 - n

  • 2 - n + n - 1

  • 2n - 1


C.

2 - n + n - 1

12 + 34 + 78 + 1516 + ...S1 = 12S2 = 12 + 34 = 2 + 34 = 54S3 = 12 + 34 + 78 = 4 + 6 + 78 = 178S4 = 178 + 1516 = 34 + 1516 = 4916Sn = 2 - n + n - 1S1 = 121 + 1 - 1 = 12S2 = 122 + 2 - 1 = 14 +1 = 54S3 = 123 + 3 - 1 = 18 + 2 = 178S4 = 124 + 4 - 1 = 116 + 3 = 4916Hence, 12 + 34 + 78 + 1516 +  ... = 2- n + n - 1


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