What is the equation of the plane passing through the points (- 2, 6, - 6), (- 3, 10, - 9) and (- 5, 0, - 6) ?
2x - y - 2z = 2
2x + y + 3z = 3
x + y + z = 6
x - y - z = 3
What is the distance of the point (2, 3, 4) from the plane 3x - 6y + 2z + 11 = 0 ?
1 unit
2 units
3 units
4 units
x + y + z = 6, x + 2y - 3z = - 4
3x + 2y - 3z = 0, 3x - 6y + 3z = - 2
3x + 2y - 3z = - 2, 3x - 6y + 3z = - 2
3x + 2y - 3z = -2, 3x - 6y + 3z = 0
B.
3x + 2y - 3z = 0, 3x - 6y + 3z = - 2
The angle of elevation of a stationary cloud from a point 25 m above a lake is 15° and the angle of depression of its image in the lake is 45°. The height of the cloud above the lake level is :
25m
25
50m
The point of intersection of the line joining the points ( - 3, 4, - 8) and (5, - 6, 4) with the XY-plane is
If the angle between the lines whose direction ratios are (2, - 1, 2) and (x, 3, 5) is ,then the smaller value of x is :
52
4
2
1