Acetaldoxime on reduction with Na/C2H5OH gives from Chemistry Am

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 Multiple Choice QuestionsMultiple Choice Questions

101.

The reaction of CHCl3 and alcoholic KOH with p-toluidine gives


102.

The correct order of increasing basic nature of the following bases is

  • 2 < 5 < 1 < 3 < 4

  • 5 < 2 < 1 < 3 < 4

  • 2 < 5 < 1 < 4 < 3

  • 5 < 2 < 1 < 4 < 3


103.

Choose the amide which on reduction with LiAlH4 yields a secondary amine

  • ethanamide

  • N-methylethanamide

  • N, N-dimethylethanamide

  • phenylmethanamide


104.

Arrange the following amines in the decreasing order of their basic strength. Aniline (I), Benzylamine (II), p-toluidine (III)

  • I > II > III

  • II > III > I

  • III > II > I

  • II > I > III


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105.

Which one of the following compounds will dissolve in an alkali solution after it has undergone reaction with Hinsberg reagent?

  • CH3NH2

  • (CH3)3N

  • (C2H5)2NH

  • C6H5NHC6H5


106.

Identify the product in the following sequence 3,4,5 tribromoaniline (2) H3PO2(1) diazorization ?

  • 3, 4, 5-tribromobenzene

  • 1, 2, 3-tribromobenzene

  • 2, 4, 6-tribromobenzene

  • 3, 4, 5-tribromonitrobenzene


107.

Among the amines 

(A) C6H5NH2

(B) CH3NH2

(C) (CH3)3N

(D) (CH3)2NH

  • A < B < D <C

  • D < C < B <A

  • A > B > C >D

  • B < C < D <A


108.

  • fiuorobenzene

  • benzene

  • 1, 2-difluoro benzene

  • 1, 3-difluoro benzene


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109.

The indicator that is obtained by coupling the diazonium salt of sulphanilic acid with N, N-dimethyl aniline is

  • phenanthroline

  • methyl orange

  • methyl red

  • phenolphthalein


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110.

Acetaldoxime on reduction with Na/C2H5OH gives

  • 2-propanol

  • ethyl amine

  • acetaldehyde

  • ethanol


B.

ethyl amine

Aldoxime and ketoxime on reduction with LiAlH4 or Na-C2H5OH give 1° amine.

CH3-CH=NOHacetaldoxime Na-C2H5OH CH3CH2NH2Ethyl amine + H2O


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