Multiple Choice QuestionsThe species in which the N atom is in a state of sp hybridization is:
NO2-
NO3-
NO2
NO2
The ionic radii (in Å) of N3–, O2– and F– are respectively:
1.36, 1.40 and 1.71
1.36, 1.71 and 1.40
1.71, 1.40 and 1.36
1.71, 1.40 and 1.36
In which of the following pairs of molecules/ions, both the species are not likely exist?
Which of the following exists as covalent crystals in the solid state?
Iodine
Silicon
Sulphur
Sulphur
Stability of the species Li2, Li2− and Li2+ increases in the order of:
Li2 < Li2+ < Li2-
Li2− < Li2+ < Li2
Li2< Li2− < Li2+
Li2< Li2− < Li2+
In which of the following pairs the two species are not isostructural?
CO32- and NO3-
PCl+4 and SiCl4
PF5 and BrF5
PF5 and BrF5
Among the following, the maximum covalent character is shown by the compound
FeCl2
SnCl2
AlCl3
AlCl3
C.
AlCl3
The covalent character in ionic compounds is governed by Fazanís Rule.
(i) larger the charge on the ions.
(ii) smaller the size of anions.
(iii) larger the size of anion.
(iv) larger the polarizing power larger the covalent character.
AlCl3 will show Maximum covalent character on account of the higher polarising power of Al3+ because of its having higher positive charge and smaller size.
The hybridization of orbitals of N atom in NO3-, NO2+ and NH4+ are respectively
sp, sp2,sp3
sp2 , sp, sp
sp, sp3 , sp2
sp, sp3 , sp2
The group having isoelectronic species is
O2– , F–, Na+ , Mg2+
O– , F–, Na, Mg+
O2–, F–, Na ,Mg2+
O2–, F–, Na ,Mg2+
Using MO theory predict which of the following species has the shortest bond length?
O22+
O2+
O2−
O2−
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