The central carbon atom of a free radical contains
6 electrons
7 electrons
8 electrons
10 electrons
Reaction for the formation of NaCl is
Na(g) + Cl2(g) → NaCl(s)
Na(s) + Cl2(g) → NaCl(s)
Na(g) + Cl2(g) → NaCl(s)
Na(g) + Cl2(g) → NaCl(g)
The hybridization state of C atom in butendioic acid is
sp2
sp3
Both (a) and (b)
sp
A.
sp2
In butendioic acid, C- atoms are sp2 hybridised.