dsp² hybridisation is found in

• [Ni(CN)₄]^2-

• [CoCl₄]^2-

• [CuCl₄]^3-

• [CuCl₄]^2-

Cold ferrous sulphate solution on absorption of NO develops brown colour due to the formation of

• paramagnetic [Fe(H₂O)₅(NO)] SO₄

• diamagnetic [Fe(H₂O)₅(N₃)] SO₄

• paramagnetic [Fe(H₂O)₅(NO₃)][SO₄]₂

• diamagnetic [Fe(H₂O)₄ (SO₄)]NO₃

Which of the following option w.r.t. increasing bond order is correct ?

• NO < C₂ <O₂^- <He₂⁺

• C₂ < NO < He₂⁺ < O₂^-

• He₂⁺ < O₂^- < NO  < C₂

• He₂⁺ < O₂^- < C₂ < NO.

The BCl₃, is a planar molecule where as NCl₃, is pyramidal. because

• B-Cl bond is more polar than N-Cl bond

• N-Cl bond is more covalent than B-Cl bond

• nitrogen atom is smaller than boron atoms

• BCl₃  has no lone pair but NCl₃ has a lone pair of electrons.

The electronic configuration is 1s² 2s² 2p⁵ 3s¹  shows

• ground state of fluorine atom

• excited state of fluorine atom

• excited state of neon atom

• excited state of ion O₂

606.

Assertion : B₂H₆, Si₂H₆, are said to have similar structure.

Reason : They have same number of $\mathrm{\sigma }$ and $\mathrm{\pi }$ bonds.

• If both Assertion and Reason are true and Reason is the correct explanation of Assertion.

• If both Assertion and Reason are true but Reason is not the correct explanation of Assertion.

• If Assertion is true but Reason is false.

• If Assertion is false but Reason is true.

Assertion: Sigma ($\mathrm{\sigma }$) is a strong bond, while pi ($\mathrm{\pi }$) is a weak bond.
Reason: Atoms rotate freely about the pi ($\mathrm{\pi }$) bond.

• If both assertion and reason are true and the reason is a correct explanation of the assertion.

• If both the assertion and reason are true but the reason is not a correct explanation of the assertion.

• If the assertion is true but the reason is false.

• If both the assertion and reason are false.

The correct order of decreasing H-C-H angle in the following molecule is

• I > II > III

• II > I > III

• III > II > I

• I > III > II

The state of hybridization of the central atom and the number of lone pairs over the central atom in POCl₃
are:

• sp , 0

• sp² , 0

• sp³ , 0

• dsp² , 1

The compound that will have a permanent dipole moment among the following is

• I

• II

• III

• IV