The order of first ionization energies of the elements Li, Be, B, Na is :
Li> Be> B > Na
Be > B > Li > Na
Na > Li > B> Be
Be > Li > B > Na
The standard adopted for the determination of atomic weight of elements is based on :
H1
C12
O16
S32
In the periodic table metallic character of elements shows one of the following trend :
decreases down the group and increases across the period
increases down the group and decreases across the period
increases across the period and also down the group
decreases across the period and also down the group
Oxygen molecule contains :
no unpaired electron
one unpaired electron
two unpaired electrons
three unpaired electrons
C.
two unpaired electrons
In oxygen molecules
Number of electrons = 8
= 1s2, 2s2, 2p4
So, the unpaired electrons are 2.
The electronic configuration of elements A, B and C are [He] 2s1, [Ne] 3s1 and [Ar] 4s1 respectively, which one of the following order is correct for the first ionization potentials (in kJ mol-1) of A , B and C?
A > B > C
C > B > A
B > C > A
C > A > B