The set representing the correct order for first ionisation potential is
K > Na > Li
Be > Mg > Ca
B > C > N
Ge > Si > C
A nuclide of an alkaline earth metal undergoes radioactive decay by emission of three -particles in succession. The group of the periodic table to which the resulting daughter element would belong to
Group 14
Group 16
Group 4
Group 6
The first ionisation enthalpy of boron is less than beryllium because:
Boron has high nuclear charge
The size of boron atom is more than beryllium atom
p-subshell of boron has only one electron
The size cit boron atom is less than beryllium atom
What will be the order of Ist ionisation energy?
Li > Na > K
K > Li > Na
Na > Li > K
Li > K > Na
A.
Li > Na > K
In a sub-group ionisation energy decreases from top to bottom because atomic size increases. So, the Ist Ionisation Energy of Li, Na and K are in the order
Li > Na > K
Which of the following statement(s) is/are correct regarding shielding effect?
The magnitude of screening effect do not depends upon the number of inner electrons
The magnitude of effective nuclear charge decreases in a period.
Greater the shielding effect, lower will be the atomic radii
For a given 'orbit' the shielding effect of electron belonging to different subshell decrease in the order s > p > d >f
The incorrect configuration is
K = [Ar] 4s1
Cr= [Ar] 3d5 ,4s1
Cr= [Ar] 3d4 , 4s1
Cu= [Ar]3d10 ,4s1