Equivalent conductance of O .0128 N acetic acid solution, at 25°C is 14 ohm-1 eq-1 and at infinite dilution is 391 ohm-1eq-1 .The degree of dissociation of acetic acid in the solution and its dissociation constant, respectively are:
0.036 and 1.66x10-5
0.121 and 1.78x10-4
0 .213 and 1.84x10-5
O .054 and 1.94x10-4
Two metals 'A' and 'B' have E, value equal to 0.36 V and 1.23 V. What will be the correct cell equation?
A + B2+ A2+ + B
A2+ + B A + B2+
Both (a) and (b)
None of the above
Ag | AgCl | Cl- (C2) || Cl- (C1) | AgCl | Ag for this cell G is negative if:
C1 = C2
C1 > C2
C2 > C1
both (a) and (b)
Rusting of iron is a chemical reaction. The reaction is :
double decomposition
combination
displacement
analysis
Which one of the following conditions will increase the voltage of the cell represents by the equation?
Cu (s) + 2Ag+ (aq) Cu2+ (aq) + Ag (s)
Increase in the concentration of Ag+ ions
Increase in the concentration of Cu2+ ions
Increase in the dimensions of silver electrode
Increase in the dimensions of copper electrode
During the electrolysis of the aqueous solution of copper sulphate using Pt electrodes , the reaction taking place at the anode is:
Cu2+ + 2e- Cu
Cu Cu2+ + 2e-
2H2O 4H+ + O2 + 4e-
H2O + e- OH- + H2
Cadmium rods are used for which purpose?
emit electrons
absorb neutrons
emit neutrons
absorb electrons
What is the effect of dilution on the equivalent conductance of strong electrolyte?
Decrease on dilution
Remains unchanged
Increase on dilution
None of the above
How many moles of Pt may be deposited on the cathode when 0.80 F of electricity is passed through a 1.0 M solution of Pt4+ ?
1.0 mol
0.20 mol
0.40 mol
0.80 mol
Calculate (in S cm2 mol-1) using appropriate molar conductances of the electrolytes listed in the given table
Electrolyte | KCl | KNO3 | HCl | NaOAc | NaCl |
(S cm2 mol-1) |
149.9 | 145.0 | 426.2 | 91.0 | 126.5 |
at infinite dilution in H2O at 25C
517.2
305.0
390.7
217.5