H2S gas when passed through a solution of cations containing HCl precipitates the cations of second group of qualitative analysis but not those belonging to the fourth group. It is because:
presence of HCl decreases the sulphide ion concentration
presence of HCl increases the sulphide ion concentration
solubility product of group II sulphides is more than that of group IV sulphides
sulphides of group IV cations are unstable in HCl
A + B C + D. If initially the concentration of A and B are both equal but at equilibrium, concentration of D will be twice of that of A, then what will be the equilibrium constant of reaction?
4/9
9/4
1/9
4
Given pH of a solutionA is 3 and it is mixed with another solution B having pH 2. If both mixed, then resultant pH of the solution will be :
3 : 2
1 : 9
3 : 4
3 : 5
When NaNO3 is heated in a closed vessel oxygen is liberated and NaNO3 is left behind,
At equilibrium:
addition of NaNO2 favours reverse reaction
addition of NaNO3 favours reverse reaction
increasing temperature favours forward reaction
decreasing temperature favours backward reaction
C.
increasing temperature favours forward reaction
:
CaO does not react to CO2 to give CaCO3
backward reaction is very low
CO2 formed escapes out
None of the above
Consider the following reversible reaction at equilibrium:
The maximum decomposition of H2O(g) will occur by which of the following change in conditions.
Increasing temperature and decreasing pressure
Decrease temperature and increasing pressure
Increasing both temperature and pressure
Increasing temperature at constant pressure
NaOH(aq), HCl(aq), and NaCl(aq) concentration of each is 10-3 M. Their pH will be respectively
10, 6, 2
11, 3, 7
10, 3, 7
10, 4, 7
On adding A to the reaction at equilibrium, AB (s) A(g) + B(g) the new equilibrium concentration of A becomes double, the equilibrium concentration of B would become:
1/2 of its original value
1/4 of its original value
1/8 of its original value
Twice its original value