pH of a saturated solution of Ca(OH)2 is 9. The solubility product(Ksp) of Ca(OH)2 is:
0.25 × 10-10
0.5 × 10-15
0.125 × 10-15
0.5 × 10-10
At 900C , pure water has [H+]=10-6 M , if 100 mL of 0.2 M HCl is added to 200mL of 0.1 M KOH at 90°C then pH of the resulting solution will be:
5
6
7
4
KMnO4 can be prepared from K2MnO4 as per reaction
The reaction can go to completion by removing OH- ions by adding
HCl
KOH
CO2
SO2
D.
SO2
Since, OH- are generated from weak acid (H2O), a weak acid (like CO2) should be used to remove it because of strong acid (HCl) reverse the reaction. KOH increases the concentration of OH-, thus again shifts the reaction in backward side. CO2 combines with OH- to give carbonate which is easily removed. SO2, reacts with water to give strong acid, so it cannot be used.
Consider the following reaction equilibrium:
Initially, 1 mole of N2 and 3 moles of H2 are taken in a 2 L flask. At equilibrium state if, the number of moles of N2 is 0.6, what is the total number of moles of all gases present in the flask?
0.8
1.6
3.2
6.4