The correct sequence of reactions to be performed to convert benz

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191.

The correct sequence of reactions to be performed to convert benzene into m-bromoaniline is

  • nitration, reduction, bromination

  • bromination, nitration, reduction

  • nitration, bromination, reduction

  • reduction, nitration, bromination


C.

nitration, bromination, reduction

Conversion of benzene into m-bromoaniline can be done by successive nitration, bromination and reduction using following reagent:

     Nitration : conc. HNO3 | conc. H2SO4

Bromination : Br2 | H2O

   Reduction : Sn | HCl

Formation of nitrobenzene in the first step direct incoming electrophile towards meta position on the further step reduction of nitro compound produces m- bromoaniline very easily. Complete sequence of the chemical reaction can be shown as-


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192.

The correct statement is

  • Cyclohexadene and cyclohexene cannot be isolated with ease during controlled hydrogenation of benzene

  • One mole each of benzene and hydrogen when reacted gives 1/3 mole of cyclohexane and 2/3 mole unreacted hydrogen

  • Hydrogenation of benzene to cyclohexane is an endothermic process

  • It is easier to hydrogenate benzene when compared to cyclohexene


193.

Number of possible alkynes with formula C5H8 is

  • 2

  • 3

  • 4

  • 5


194.

Benzene carbaldehyde is reacted with conc. NaOH solution to give the products A and B. The product A can be used as a food preservative and the product B is an aromatic hydroxy compound, where -OH group is linked to sp3-hybridised C-atom next to benzene ring. The products A and B respectively are

  • sodium benzoate and phenol

  • sodium benzoate and phenyl methanol

  • sodium benzoate and cresol

  • sodium benzoate and picric acid


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195.

The arrangement of following compounds.

(i) Bromomethane

(ii) Bromoform

(iii) Chloromethane

(iv) Dibromomethane

In the increasing order of their boiling point is

  • III < I < IV < II

  • IV < III < I < IV

  • II < III < I < IV

  • I < II < III < IV


196.

An organic compound A on reduction gives compound B, which on reaction with trichloromethane and caustic potash forms C. The compound C on catalytic reduction gives N-methyl benzenamine, the compound A is,

  • nitrobenzene

  • nitromethane

  • methanamine

  • benzenamine


197.

Which of the following has highest knocking ?

  • Olefins

  • Branched chain olefins

  • Straight chain olefins

  • Aromatic hydrocarbons


198.

Chlorination of benzene is not possible in the following reaction :

  • C6H6 + Cl2 FeCl3

  • C6H6 + HOCl H+

  • C6H+ I-Cl ZnCl2

  • C6H+ Cl2 AlCl3


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199.

In which of the following, homolytic bond fission takes place?

  • Free radical chlorination of methane

  • Addition of HBr to double bond

  • Alkaline hydrolysis of ethyl chloride

  • Nitration of benzene


200.

A petroleum fraction having boiling range 70-200°C and containing 6-10 carbon atoms per molecule is called :

  • natural gas

  • gas oil

  • gasoline

  • kerosene


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