The oxidation number of C atom in CH2Cl2 and CCl4 are respectivel

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

11.

The standard Ered° values of A, B  and C are +0.68 V, - 2.54 V,- 0.50 V respectively. The rder of their reducing power is

  • A> B >C

  • A> C > B

  • C > B > A

  • B > C > A


12.

Oxidation potential of unimoles of calomel is

  • + 0.25 V

  • 0.00 V

  • + 0.287 V

  • -0.28 V


Advertisement

13.

The oxidation number of C atom in CH2Cl2 and CCl4 are respectively

  • -2 and -4

  • 0 and -4

  • 0 and 4

  • 2 and 4


C.

0 and 4

Let the oxidation number of C be x

CH2Cl2 - x +2(+1) + 2(-1) = 0

                          x + 2 - 2 = 0

                                     x = 0

CCl4 - x + 4(-1) = 0

                x - 4 = 0

                     x = 4

Therefore, oxidation number of CH2Cl2 is 0 and CCl4 is 4.


Advertisement
14.

The oxidation state of Cr in K2Cr2O7 is

  • +4

  • +3

  • +6

  • +5


Advertisement
15.

Potassium dichromate is a good oxidising agent in acidic medium, the oxidation state of chromium changes by

  • 2

  • 3

  • 4

  • 5


16.

Which among the following compounds does not act as reducing agent?

  • H2O

  • H2S

  • H2Se

  • H2Te


17.

Which among the following equations represents the reduction reaction taking place in lead accumulator at positive electrode, while it is being used as a source of electrical energy?

  • Pb → Pb2+

  • Pb4+ → Pb

  • Pb2+ → Pb

  • Pb4+ → Pb2+


18.

When MnO2 is fused with KOH and KNO2 , a coloured compound is formed. Choose the right compound with the appropriate colour.

  • K2MnO4, green

  • KMnO4, purple

  • Mn2O3, brown

  • Mn3O4, black


Advertisement
19.

Identify the case(s) where there is change is oxidation number

  • Acidified solution of CrO42-

  • SO2 gas bubbled through an acidic solution Cr2O72-

  • Alkaline solution of CrO72-

  • Ammoniacal solution of CrO42-


20.

In aqueous solution, Cr2+ is a stronger reducing agent than Fe2+. This is because

  • Cr2+  ion is more stable than Fe2+

  • Cr3+ ion with d3 configuration has favourable crystal field stabilisation energy

  • Cr3+ has half filled configuration and hence more stable

  • Fe3+ in aqueous solution is more stable than Cr3+


Advertisement