Four solutions A, B, C, D has glucose 0.5 M, NaCl 0.1 M, BaCl2 0.

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 Multiple Choice QuestionsMultiple Choice Questions

121.

120 gm urea is present in 5 L solution, the active mass of urea is

  • 0.2

  • 0.06

  • 0.4

  • 0.08


122.

The vapour pressure ofa pure liquid 'A' is 0.80 atm. When a non-volatile solute 'B' is dissolved in 'A' its vapour pressure becomes 0.60 atm. The mole fraction of 'B' in the solution is

  • 0.125

  • 0.25

  • 0.50

  • 0.75


123.

Which of the following does not show negative deviation from Raoult's law?

  • Acetone -Chloroform

  • Acetone-Benzene

  • Chloroform- Ether

  • Chloroform- Benzene


124.

50mL of benzene is mixed with 50mL of chloroform. What is the volume of solution?

  • Less than 100 mL

  • More than 100 mL

  • Equal to 100 mL

  • None of the above


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125.

Which of the following is a colligative property?

  • Surface tension

  • Viscosity

  • Osmotic pressure

  • Vapour pressure


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126.

Four solutions A, B, C, D has glucose 0.5 M, NaCl 0.1 M, BaCl2 0.5 M and MgCl2 0.1 M, then which of the following will have highest osmotic pressure?

  • Glucose

  • BaCl2

  • MgCl2

  • NaCl


B.

BaCl2

Molar concentration of glucose = 0.5 M

Molar concentration of NaCl = 0.1 M

Molar concentration of BaCl2 = 0.5 M

Molar concentration of MgCl2 = 0.1 M

However as NaCl, BaCl2 and MgCl2 is an electrolyte. One mole of NaCl give two mole ions, therefore molar concentration of particles in the solution = 0.2 M.

One mole of BaCl2 give three mole ions, therefore molar concentration of particles in the solution = 1.5 M.

and one mole of MgCl2 give three mole ions, therefore molar concentration of particles in solution = 0.3 M.

As, osmotic pressure is directly proportional to the number of particles in the solution, hence, increasing order ofosmotic pressure will be.

Glucose < NaCl < MgCl2 < BaCl2


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127.

The highest boiling point is of

  • FeCl2

  • FeCl3

  • Al2(SO4)3

  • AlCl3


128.

The volume strength of 1.5 N H2O2 solution is

  • 8.4

  • 4.8

  • 5.2

  • 8.8


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129.

On dissolving a non-volatile solute in a solvent, the vapour pressure of the solvent is decreased by 10 mm of mercury. The mole fraction of the solute in this solution is 0.2. If the vapour pressure of the solvent is decreased by 20 mm of mercury by dissolving more solute, what is the mole fraction of solvent in this solution now?

  • 0.2

  • 0.4

  • 0.6

  • 0.8


130.

During osmosis, flow of water through a semi-permeable membrane is

  • from both sides of semi-permeable membrane with equal flow rate

  • from solution having lower concentration only

  • from solution having higher concentration only

  • None of the above


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