58.4 g of NaCl and 180 g of glucose were separately dissolved in l000mL of water. Identify the correct statement regarding the elevation of the boiling point (b.p) of the resulting solutions.

• NaCl solution will show higher elevation of boiling point

• Glucose solution will show higher elevation of boiling point

• Both the solutions will show equal elevation of boiling point

• The boiling point elevation will be shown by neither of the solutions

Which of the following will show a negative deviation from Raoult's law?

• Acetone-benzene

• Acetone-ethanol

• Benzene-methanol

• Acetone-chloroform

To observe an elevation of boiling point of 0.05°C, the amount of a solute (mol. wt. = 100) to be added to 100 g of water (K_b = 0.5) is

• 2 g

• 0.5 g

• 1 g

• 0.75 g

Solubility product of Mg(OH)₂ at ordinary temperature is 1.96 × 10^-11 pH of a saturated solution of Mg(OH)₂ will be

• 10.53

• 8.47

• 6.94

• 3.47

The freezing point of water is depressed by 0.37°C in a 0.01 molal NaCl solution. The freezing point of 0.02 molal solution of urea is depressed by

• 0.37°C

• 0.74°C

• 0.185°C

• 0°C

Chloroform, when kept open, is oxidised to :

• CO₂

• COCl₂

• CO₂, Cl₂

• None of these

Blood cells will remain as such in:

• hypertonic solution

• hypotonic solution

• isotonic solution

• none of the above

The mixture that forms maximum boiling azeotrope is:

• Ethanol + Water

• Acetone + Carbon disulphide

• Heptane + Octane

• Water + Nitric acid

329.

For an ideal solution, the correct option is :

• Δ_mix V ≠  0 at constant T and P

• Δ_mix H =  0 at constant T and P

• Δ_mix G =  0 at constant T and P

• Δ_mix S = 0 at constant T and P