The ratio of mass percent of C and H of an organic compound (CXHY

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 Multiple Choice QuestionsMultiple Choice Questions

1.

20 mL solution of 0.1 M ferrous sulphate was completely oxidised using a suitable oxidising agent. What is the number of electrons exchanged?

  • 1.204 x 1022

  • 193

  • 1930

  • 1.204 x 1021


2.

The molecular formula of a commercial resin used for exchanging ions in water softening is C8H7SO3Na ( mol. wt = 206). What would be the maximum uptake of Ca2+ ions by the resin when expressed in mole per gram resin?

  • 1/103

  • 1/206

  • 2/309

  • 2/309

920 Views

3.

In Carius method of estimation of halogens, 250 mg of an organic compound gave 141 mg of AgBr. The percentage of bromine in the compound is: (at. Mass Ag = 108; Br = 80)

  • 24

  • 36

  • 48

  • 48

463 Views

4.

A gaseous hydrocarbon gives upon combustion 0.72 g of water and 3.08 g of CO2.The empirical formula of the hydrocarbon is 

  • C2H4

  • C3H4

  • C6H5

  • C6H5

428 Views

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5.

Experimentally it was found that a metal oxide has formula M0.98O. Metal M, is present as M2+ and M3+ in its oxide. The fraction of the metal which exists as M3+ would be:

  • 7.01%

  • 4.08%

  • 6.05%

  • 6.05%

411 Views

6.

The most abundant element by mass in the body of a healthy human adult are :
Oxygen (61.4%) ; Carbon (22.9%), Hydrogen(10.0%) ; and Nitrogen (2.6%). The weight which a 75 kg person would gain if all 1H atoms are replaced by 2H atoms is

  • 15 kg

  • 37.5 Kg

  • 7.5 Kg

  • 7.5 Kg

1085 Views

7.

How many moles of magnesium phosphate, Mg3(PO4)2 will contain 0.25 mole of oxygen atoms?

  • 0.02

  • 3.125 × 10–2

  • 1.25 × 10–2

  • 1.25 × 10–2

339 Views

8.

If we consider that 1/6 in place of 1/12 mass of carbon atom is taken to be the relative atomic mass unit, the mass of one mole of a substance will 

  • Decrease twice

  • Increase two fold

  • Remain unchanged

  • Remain unchanged

149 Views

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9.

The ratio of mass percent of C and H of an organic compound (CXHYOZ) is 6: 1. If one molecule of the above compound (CXHYOZ) contains half as much oxygen as required to burn one molecule of compound CXHY completely to CO2 and H2O. The empirical formula of compound CXHYOZ is

  • C2H4O3

  • C3H6O3

  • C2H4O

  • C3H4O2


A.

C2H4O3

The ratio of mass % of C and H in CxHyOz is 6: 1.
Therefore,
The ratio of mole % of C and H in CxHyOz will be 1: 2.
Therefore x : y = 1 : 2, which is possible in options 1, 2 and 3.
Now oxygen required to burn CxHy

CxHy + x + y4O2      xCO2 + y2H2O

Now z is half of the oxygen atoms required to burn CxHy

 z = (2x +y2)2 = x + y4

Now putting values of x and y from the given options:
Option (1), x = 2, y = 4

z = 2 + 44 = 3Option 2, x = 3, y = 6z = 3 + 64 = 4.5Therefore correnct (C2H4O3)


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10.

0.126 g of an acid is needed to completely neutralise 20 mL 0.1 (N) NaOH solution. The equivalent weight of the acid is

  • 53

  • 40

  • 45

  • 63


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