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 Multiple Choice QuestionsMultiple Choice Questions

151.

When a liquid that is immiscible with water was steam distilled at 95.2°C at a total pressure of 99.652 kPa. The distillate contained 1.27 g of the liquid per gram of water. What will be the molar mass of the liquid if the vapour pressure of water is 85.140 kPa at 95.2°C?

  • 99.65 g mol-1

  • 18 g mol-1

  • 134.1 g mol-1

  • 105.74 g mol-1


152.

Van der waals' real gas, acts as an ideal gas at which condition?

  • High temperature, low pressure

  • Low temperature, high pressure

  • High temperature, high pressure

  • Low temperature, low pressure


153.

Which of the following type of forces are present in vulcanised rubber?

  • Weakest intermolecular forces

  • Hydrogen bonding

  • Three dimensional network of bonds

  • Metallic bonding


154.

Match the following

List I List II
(A) Viscosity (I) Critical temperature
(B) Ideal gas behaviour (II) Isobar
(C) Liquefaction of gases (III) Compressibility factor
(D) Charles'law (IV) kg s-2
  (V) kgm-1s-1

The correct answer

  • A-IV, B-III, C-I, D-II

  • A-V, B-III, C-I, D-II

  • A-V, B-III, C-II, D-I

  • A-IV, B-III, C-II, D-I


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155.

The most probable speed of O2, molecules at T(K) is

  • RT4π

  • RT16π

  • RT16

  • 3RT32


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156.

If the kinetic energy in J, of CH4 (molar mass =16 g mol-1) at T(K) is X, the kinetic energy in J, of O2, (molar mass = 32 g mol-1) at the same temperature is

  • X

  • 2X

  • X2

  • X/2


A.

X

At same temperature, kinetic energy of both the gases will be same. In short
                          KE ∝√T                     (for all gases)

                          KE(CH4) = KE(O2)= X 


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157.

The given figure shows the Maxwell distribution of molecular speeds of a gas at three different temperatures T1,T2, and T3. The correct order of temperature is

       

  • T1 > T2 > T3

  • T1 > T3 > T2

  • T3 > T2 > T1

  • T2 > T3 > T1


158.

At low pressure and high temperature, the van der Waal's equation is finally reduced (simplified) to

  • p + aVm2(Vm - b) = RT

  • p(Vm - b) = RT

  • p + aVm2Vm = RT

  • pVm = RT


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159.

At a given temperature T, gases Ne, Ar, Xe and Kr are found to deviate from ideal gas behaviour. Their equation of state is given as p = RTV - b at T. Here, b is the van der Waals constant. Which gas will exhibit steepest increase in the plot of Z (compression factor) vs p?

  • Ne

  • Xe

  • Ar

  • Kr


160.

Consider the following table:

Gas a/(kPa dm6mol-1) b/(dm3mol-1)
A 642.32 0.05196
B 155.21 0.04136
C 431.91 0.05196
D 155.21 0.4382

And b are vander walls contants . The correct statement a Bout the gases is :

  • Gas A will occupy than gas D  Compressible than gas D Gas C will Occupy more volume than

  • gas A gas B will be more compressible than gas D Gas C will Occupy Lesser volume than

  • Gas A gas B will be more compressible than gas D Gas C will Occupy Lesser volume than

  • Gas A: gas B will be lesser Compressble than gas D


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