A near UV photon of 300 nm is absorbed by a gas and then re-emitted as two photons. One photon is red with wavelength 760 nm. Hence, wavelength of the second photon is
1060 nm
496 nm
300 nm
215 nm
B.
496 nm
Energy values are additives.
E = E1 + E2
or,
or,
or,
On solving, λ = 495.6 nm ≈ 496 nm
What transition in the hydrogen spectrum would have the same wavelength as the Balmer transition, n = 4 to n = 2 of He+ spectrum?
n = 4 to n = 2
n = 3 to n = 2
n = 2 to n = 1
n = 4 to n = 3
In successive emission of -and -particles, the number of -and -particles should be emitted for the conversion of 92U238 to 82P206 are
An element xAy emits 5 α and 4β particles to give 82B207. The number of protons and neutrons in A are respectively
88, 227
88, 139
82, 227
84, 139