The angular momentum of electrons in d orbital is equal to

What is the maximum number of orbitals that can be identified with the following quantum numbers?

n=3, l =1, m₁ = 0

• 1

• 2

• 3

• 3

Calculate the energy in joule corresponding to light of wavelength 45mm: (Planck's constant h=6.63 x10^-34)Js; speed of light c= 3 x 10⁸ ms^-1)

• 6.67 x 10¹⁵

• 6.67 x 10¹¹

• 4.42 x 10^-15

• 4.42 x 10^-15

The value of Planck's constant is 6.63 x 10^-34 Js. The speed of light is 3 x10¹⁷ nms^-1 . Which value is closet to the wavelength in nanometer of a quantum of light with frequency of 6 x 10¹⁵ s^-1 ?

• 10

• 25

• 50

• 50

What is the maximum number of electrons that can be associated with the following set of quantum number?
n=3, l =1 and m=-1.

• 10

• 6

• 4

• 4

Based on equation
E=-2.178 x 10^-18 J  certain conclusions are written. Which of them is not correct?

• The negative sign in the equation simply means that the energy of an electron bound to the nucleus is lower than if would be if the electrons were at the infinite distance from the nucleus.

• Larger the value of n, the larger is the orbit radius

• Equation can be used to calculate the change in energy when the electron changes orbit

• Equation can be used to calculate the change in energy when the electron changes orbit

Maximum number of electrons in a subshell with l =3 and n=4 is

• 14

• 16

• 10

• 10

The correct set four quantum number for the valence electron of rubidium atom (z=37) is 

• 5,1,1, +1/2

• 6,0,0,+1/2

• 5,0,0 +1/2

• 5,0,0 +1/2

The orbital angular momentum of p-electron is given as

280.

The total number of atomic orbitals in fourth energy level of an atom is 

• 16

• 32

• 4

• 8