The unit cell length of sodium chloride crystal is 564 pm. Its de

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 Multiple Choice QuestionsMultiple Choice Questions

11.

Total volume of atoms present in a face-centre cubic unit cell of a metal is (r is atomic radius)

  • 20πr3/3

  • 24πr3/3

  • 12πr3/3

  • 12πr3/3

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12.

An ionic compound has a unit cell consisting of A ions at the corners of a cube and B ions on the centres of the faces of the cube. The empirical formula for this compound would be

  • A2B

  • AB

  • AB3

  • AB3

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13.

Lattice energy of an ionic compounds depends upon

  • Charge on the ion only

  • Size of the ion only

  • Packing of ions only

  • Packing of ions only

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14.

Based on lattice energy and other considerations which one of the following alkali metal chlorides is expected to have the highest melting point.

  • LiCl

  • NaCl

  • KCl

  • KCl

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15.

What type of crystal defect is indicated in the diagram below?

  • Frenkel defect

  • Frenkel and Schottky defects

  • Interstitial defect

  • Interstitial defect

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16.

Which type of ‘defect’ has the presence of cations in the interstitial sites?

  • Metal deficiency defect

  • Schottky defect

  • Vacancy defect

  • Frenkel defect


17.

In a close-packed body-centred cubic lattice of potassium, the correct relation between the atomic radius (r) of potassium and the edge-length (a) of the cube is

  • r = a2

  • r = a3

  • r = 32a

  • r = 34a


18.

Ionic solids with Schottky defect may contain in their structure

  • cation vacancies only

  • cation vacancies and interstitial cations

  • equal number of cation and anion vacancies

  • anion vacancies and interstitial anions


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19.

Suppose the mass of a single Ag-atom is m. Ag metal crystallises in fcc lattice with unit cell of length a. The density of Ag metal in terms of a and m is

  • 4ma3

  • 2ma3

  • ma3

  • m4a3


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20.

The unit cell length of sodium chloride crystal is 564 pm. Its density would be

  • 1.082 g cm-3

  • 2.165 g cm-3

  • 3.247 g cm-3

  • 4.330 g cm-3


B.

2.165 g cm-3

In sodium chloride unit cell, there are four Na+ and four Cl- ions.
Hence,

density =  mass of atoms in a unit cellvolume of a unit cell =M2a3NAEach unit cel of NaCl4 Na- and 4 Cl- 2 ions  Z= 4  = 4 (23 + 35.5) g mol-1(6.023× 1023 mol-1) ×( 564 ×10-12cm)3 = 2.165 g cm-3


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