A compound is formed by elements A and B. This crystallises in the cubic structure where the A atoms are at the corers of the cube and B atoms are at the body centres. The simplest formula of the compound is
AB
A6B
A8B4
AB6
A compound of 'A' and 'B' crystallises in a cubic lattice in which 'A' atoms occupy the lattice points at the corners of the cube. The 'B' atoms occupy the centre of each face of the cube. The probable empirical formula of the compound is
AB2
A3B
AB
AB3
Volume occupied by single CsCl ion pair in a crystal is 7.014 × 10-23 cm3. The smallest Cs-Cs internuclear distance is equal to length of the side of the cube corresponding to volume of one CsCl ion pair. The smallest Cs to Cs internuclear distance is nearly
4.4 Å
4.3 Å
4 Å
4.5 Å
Metallic lustre is due to
high density of metals
high polish on the surface of metals
reflection of light by mobile electrons
chemical inertness of metals
The unit cell with crystallographic dimensions, a≠b≠c,α=γ=90 and β≠ 90 is
triclinic
monoclinic
orthorhombic
tetragonal
Sodium metal crystallises in bee lattice with edge length of 4.29 Å. The radius of sodium atom is
2.857 Å
1.601 Å
2.145 Å
1.857 Å
A crystalline sold XY3 has ccp arrangement for its element Y. X occupies
66% of tetrahedral voids
33% of tetrahedral voids
66% of octahedral voids
33% of octahedral voids
D.
33% of octahedral voids
In ccp arrangement, a unit cell has total 4 particles. To keep formula XY3, number of X particles = 4/3 = 1.33.
Since, in ccp arrangement, octahedral sites = 4.
Therefore, % of X particles occupying octahedral voids = = 33%
Schottky defect in a crystal is observed, when
unequal number of cations and anions are missing from the lattice
equal number of cations and anions are missing from the lattice
an ion leaves its normal site and occupies an interstitial site
no ion is missing from its lattice site