Which one of the following does not correctly represent the corr

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 Multiple Choice QuestionsMultiple Choice Questions

201.

Which one of the following statements is correct when SO2 is passed through acidified K2Cr2O7 solution?

  • The solution is decolourized

  • SO2 is reduced

  • Green Cr2(SO4)3 is formed

  • The solution turns blue


202.

Because of lanthanoid contraction, of elements which of the following elements have nearly same atomic radii ? (Number in the parenthesis are atomic number).

  • Ti (22) and Zr(40)

  • Zr(40) and Nb (41)

  • Zr (40) and Hf (72)

  • Zr (40) and Hf (72)

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203.

In acidic medium,H2O2 changes Cr2O72- to CrO5 which has two (-O-O-) bonds. Oxidation state of Cr in CrO3 is 

  • +5

  • +3

  • +6

  • +6

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204.

Reason of lanthanoid contraction is

  • negligible Screening effect of 'f' orbitals

  • increasing the nuclear charge

  • decreasing the nuclear charge

  • decreasing the nuclear charge

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205.

Which of the following does not give oxygen on heating?

  • KClO3

  • Zn(ClO3)2

  • K2Cr2O7

  • K2Cr2O7

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206.

Which of the following lanthanoid ions is diamagnetic?
(At. number; Ce =58, Sm =62, Eu =63, Yb = 70)

  • Ce2+

  • Sm2+

  • Eu2+

  • Eu2+

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207.

KMnO4 can be prepared from K2MnO4 as per reaction
3 MnO subscript 4 superscript 2 minus end superscript space plus 2 straight H subscript 2 straight O space rightwards harpoon over leftwards harpoon 2 MnO subscript 4 superscript minus space plus MnO subscript 2 space plus 4 OH to the power of minus
The reaction can go to completion by removing OH- ions by adding

  • HCl

  • KOH

  • CO2

  • CO2

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208.

Which one of the following does not correctly represent the correct order of the property indicated aginst it? 

  • Ti < V<Cr< Mn: increasing number of oxidation states

  • Ti< V<Cr3+<Mn3+ : increasing magnetic moment

  • Ti < V < Cr < Mn : Increasing melting points

  • Ti < V < Cr < Mn : Increasing melting points


C.

Ti < V < Cr < Mn : Increasing melting points

Element

Oxidation states

Ti

+2,+3,+4

V

+2,+3,+4,+5

Cr

+1,+2,+3,+4,+5,+6

Mn

+1,+2,+3,+4,+5,+6,+7

Therefore, order of oxidation states is

Ti < V < Cr < Mn

b)

Ion

Outermost electronic arrangement

No. of unpaired electrons

Ti3+

3d1

1

V3+

3d2

2

Cr3+

3d3

3

Mn3+

3d4

4

Therefore, order of magnetic moment is

Ti3+ < V3+ < Cr3+ < Mn3+

In 3d- series melting point increases as we move from left to right. But Mn shows low melting point due to its complex formatting nature. It is unable to form metallic and covalent bonds.

Element

Second ionisation enthalpy

Ti

1320

V

1376

Mn

1513

Cr

1635

 Therefore, order of second ionisation enthalpy is

Ti< V< Mn< Cr

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209.

Four successive members of the first series of the transition metals are listed below. For which one of them, the standard potential valueleft parenthesis straight E subscript straight M to the power of 2 plus end exponent divided by straight M end subscript superscript straight o right parenthesis has a positive sign?

  • Co (Z=27)

  • Ni (Z=28)

  • Cu (Z=29)

  • Cu (Z=29)

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210.

The catalytic activity of transition metals and their compounds is ascribed mainly to

  • their magnetic behaviour

  • their unfilled d- orbitals

  • their ability to adopt variable oxidation states

  • their ability to adopt variable oxidation states

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