What is the amount of work done when 0.5 mole of methane, CH4(g), is subjected to combustion at 300 K? (Given, R=8.314JK-1 mol-1)
-2494 J
-4988 J
+ 4988 J
+ 2494 J
In the reaction; A2(g) + 3B2(g) → 2AB3(g), the standard entropies in (JK-1 mol-1) of A2(g), B2(g) and AB3(g) are respectively 190, 130 and 195 and the standard enthalpy change for the reaction is -95 kJ mol-1. The temperature (in K) at which the reaction attains equilibrium is (assuming both the standard entropy change and standard enthalpy change for this reaction are constant over a wide range of temperature)
500
400
300
200
Calculate the standard enthalpy change (in kJ mol-1) for the reaction
H2(g) + O2(g) → H2O2(g)
Given that bond enthalpies of H-H, O=O, O-H and O-O (in KJ mol-1) are respectively 438, 498, 464 and 138.
-130
-65
+130
-334
According to the first law of thermodynamics which of the following quantities represents the change in a state function?
qrev + Wrev
qrev
qrev - Wrev
qrev / Wrev
If the activation energy for the forward reaction is 150 kJ mol-1 and that of the reverse reaction is 260 kJ mol-1, what is the enthalpy change for the reaction?
410 kJ mol-1
110kJ mol-1
-110 kJ mol-1
-410 kJ mol-1
C.
-110 kJ mol-1
Enthalpy change for a reversible reaction,
ΔH = Ea (forward)- Eb (backward)
ΔH = 150 - 260 = -110 kJ mol-1
When 0.2 g of 1-butanol was burnt in a suitable apparatus, the heat evolved was sufficient to raise the temperature of 200 g water by 5°C. The enthalpy of combustion of 1-butanol in kcal mol-1 will be
+37
+370
-370
-740
Given that dE = Tds - pdV and H = E + pV. Which one of the following relations is true ?
dH = TdS + Vdp
dH = SdT + Vdp
dH = -SdT + Vdp
dH = dE + pdV
Using the following thermochemical equations
(i) S(rh) + 3/2O2(g) → SO3 (g) ΔH = -2x kJ mol-1
(ii) SO2(g) + 1/2O2 (g) → SO3 (g) ΔH = -y kJ mol-1
Find out the heat of formation of SO2 (g) in kJ mol-1.
(2x + y)
(x + y)
(2x/y)
(y- 2x)
The activation energy of exothermic reaction A → B is 80 kJ mo1-1. The heat of reaction is 200 kJ mol-1. The activation evergy for the reaction B → A (in kJ mol-1) will be
280
200
120
40
What would be the heat released when an aqueous solution containing 0.5 mole of HNO3 is mixed with 0.3 mole of OH- (enthalpy of neutralization is -57.1 k.J) ?
28.5 kJ
17.1 kJ
45.7 kJ
1.7 kJ