A transformer having efficiency of 90% is working on 200 V and 3 kW power supply. If the current in the secondary coil is 6 A, the voltage across the secondary coil and the current in the primary coil respectively are:
300 V, 15 A
450 V, 15 A
450 V, 13.5 A
450 V, 13.5 A
In an AC circuit, an alternating voltage 100t volt is connected to a capacitor of capacity 1μF. The rms value of the current in the circuit is
100 mA
200 mA
20 mA
20 mA
An AC voltage is applied to a resistance R and an inductor L in series. If R and the inductive reactance are both equal to 3Ω, the phase difference between the applied voltage and the current in the circuit is
π/4
π/2
zero
zero
In the given figure, a diode D is connected to an external resistance R = 100 Ω and an e. m. f of 3.5 V. If the barrier potential developed across the diode is 0.5 V, the current in the circuit will be
30 mA
40 mA
20 mA
20 mA
A.
30 mA
Given, external resistance R = 100 Ω and an emf is 3.5 V.
Potential barrier across the diode is 0.5 V
Potential difference on R = 3.5 V - 0.5 V = 3.0 V
Current in circuit, I = V/R = 3/100
= 0.03 A = 30 mA
A 220 V input is supplied to a transformer. The output circuit draws a current 2.0 A at 440 V. If the efficiency of the transformer is 80%, the current drawn by the primary windings of the transformer is
3.6 A
2.8 A
2.5 A
2.5 A
The two ends f a rod of length L and a uniform cross -sectional area A are kept at two temperatures T1 and T2 (T2 > T1) .The rate of heat transfer, dQ/dt, through the rod in steady state is given by
A galvanometer having a coil resistance of 60 Ω shows full-scale deflection when a current of 1.0 A passes through it. It can be converted into an ammeter to read currents up to 5.0 A by
putting in parallel a resistance of 240 Ω
putting in series a resistance of 15 Ω
putting in series a resistance of 240 Ω
putting in series a resistance of 240 Ω
In an AC circuit, the emf (e) and the current (i) at any instant are given respectively by
e = E0 sin ωt
i = Io sin (ωt -Φ)
The average power in the circuit over one cycle of AC is
In the circuit shown, the current through the 4 Ω resistor is 1 A when the points P and M are connected to a DC voltage source. The potential difference between the point M and N is
1.5 V
1.0 V
0.5 V
0.5 V