Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

141.

In the circuit grven E =6.0 volt, R1 = 100 Ω, R2 = R3 = 50 Ω, R4 = 75 Ω. The equivalent resistance of the circurt, in ohms, is

                 

  • 11.875

  • 26.31

  • 118.75

  • None of these


142.

Two resistances are connected in two gaps of a metre bridge. The balance point is 20 cm from the zero end. A resistance of 15 ohms is connected in series with the smaller of the two. The null point shifts to 40 cm. The value of the smaller resistance in ohms is

  • 3

  • 6

  • 9

  • 12


143.

If the potential difference across the internal resistancer is equal to the emf E of the battery, then

             

  • R = r1 + r2

  • R = r1r2

  • R = r1 − r2

  • R = r2r1


144.

By using only two resistance coils-singly, in senes or in parallel one should be able to obtain resistances of 3, 4, 12 and 16 ohms. The separate resistances of the coil are

  • 3 and 4

  • 4 and 12

  • 12 and 16

  • 16 and 3


Advertisement
145.

In the given circuit, the voltmeter records 5 volts. The resistance of the voltmeter in ohms is

                    

  • 200

  • 100

  • 10

  • 50


146.

When a body falls in air, the resistance of air depends to a great extent on the shape of the body. 3 different shapes are given. Identify the combination of air resistances which truly represents the physical situation. (The cross-sectional areas are the same).

       

1. Disc                2. Ball           3. Cigar shaped

  • 1 < 2 < 3

  • 2 < 3 < 1

  • 3 < 2 < 1

  • 3 < 1 < 2


Advertisement

147.

The magnitude of I m ampere is

            

  • 0.1

  • 0.3

  • 0.6

  • none of these


A.

0.1

All the resistances are in parallel order, so voltage across them will be equal

       

∴                   60 I = (15 + 5) I1

⇒                  60 I = 20 I1

⇒                     I1 = 3 I                    ....... (i)

Again, (15 + 5) I1 = 10 (1 − I − I1)

⇒                   2I1 = 1 − I − I1

⇒                2(3I) = 1 − I − I1

⇒             6I + 4I = 1

⇒                  10 I = 1

∴                        I = 110 = 0.1 A


Advertisement
148.

A battery of emf 10 V and internal resistance 3 Ω is connected to a resistor. The current in the circuit is 0.5 A. The terminal voltage of the battery when the circuit is closed is

  • 10 V

  • 0 V

  • 1.5 V

  • 8.5 V


Advertisement
149.

The electron dirft speed is small and the charge of the electron is also small but still, we obtain large current in a conductor. This is due to

  • the conducting property of the conductor

  • the resistance of the conductor is small

  • the electron number density of the conductor is small

  • the electron number density of the conductor is enormous


150.

In the circuit shown, the value of I in ampere is

      

  • 1

  • 0.60

  • 0.4

  • 1.5


Advertisement