Pick out the statement which is incorrect ?
A negative test charge experiences a force opposite to the direction of the field
The tangent drawn to a line of force represents the direction of electric field
Field lines never intersect
The electric field lines forms closed loop
Two spheres carrying charges + 6 µC and + 9 µC, separated by a distance d, experiences a force of repulsion F. When a charge of −3 μC is given to both the spheres and kept at the same distance as before, the new force of repulsion is
F
3F
A spherical shell of radius 10 cm is carrying a charge q. If the electric potential at distances 5 cm, 10 cm and 15 cm from the centre of the spherical shell is V1, V2 and V3 respectively, then
V1 = V2 > V3
V1 > V2 > V3
V1 = V2 < V3
V1 < V2 < V3
If there are only one type of charge in the universe, then (E → Electric field , dS → Area vector)
on any surface
if charge is inside
if charge is outside, = if charge is inside
An electron of mass m, charge e falls through a distance h metre in a uniform electric field E. Then, time of fall
If Eax and Eeq represents electric field at a point on the axial and equatorial line of a dipole. If points are at a distance r from the centre of the dipole, for r >> a
Eax = Eeq
Eax = − Eeq
Eax = − 2 Eeq
Eeq = 2 Eax
A particle of mass 1 g and charge 1 µC is held at rest on a frictionless horizontal surface at distance 1 m from the fixed charge 2 mC. If the particle is released, it will be repelled. The speed of the particle when it is at a distance of 10 m from the fixed charge.
60 ms-1
100 ms-1
90 ms-1
180 ms-1
The quantity of a charge that will be transferred by a current flow of 20 A over 1 h 30 min period is
10.8 × 103 C
10.8 × 104 C
5.4 × 103 C
1.8 × 104 C
Two point charges A = +3 nC and B=+ 1 nC are placed 5 cm apart in air. The work done to move charge B towards A by 1 cm is
2.0 × 10-7 J
2.7 × 10-7 J
1.21 × 10-7 J
1.35 × 10-7 J
D.
1.35 × 10-7 J
Given,
A = + 3 nC = 3 × 10-9 C
B = + 1 nC = 1 × 10-9 C
Distance, r1 = 5 cm = 0.05 m = 5 × 10-2 m
Work done (W) = UB − UA
=
Here, r2 = r1 − 1
r2 = 5 − 1 = 4 cm = 0.04 m = 4 × 10-2 m
4 x 1010 electrons are removed from a neutral metal sphere of diameter 20 cm placed in air. The magnitude of the electric field (in NC-1) at a distance of 20 cm from its centre is
640
5760
Zero
1440