The electric potential at a point (x, y, Z) is given byV = - x2y

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 Multiple Choice QuestionsMultiple Choice Questions

111.

In a region, the potential is represented by V (x,y,z) = 6x - 8 xy - 8y + 6yz, where V is in volts and x, y, z are in metres. The electric force experienced by a charge of 2 coulomb situated at point (1,1,1) is,

  • 6√5 N

  • 30 N

  • 24 N

  • 24 N

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112.

A charge Q is enclosed by a Gaussian spherical surface of radius R. If the radius is doubled, then the outward electric flux will 

  • be reduced to half

  • remain the same

  • be doubled

  • be doubled

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113.

A beam of cathode rays is subjected to crossed Electric (E)  and magnetic field (B). The fields are adjusted such that the beam is not deflected. The specific charge of the cathode rays is given by  

(Where V is the potential difference between cathode and anode)

  • B2/2VE2

  • 2VB2/E2

  • 2VE2/B2

  • 2VE2/B2

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114.

The square surface of side L metre in the plane of the paper is placed in a uniform electric field E (volt/m) acting along the same place at angle θ with the horizontal side of the square as shown in the figure. The electric flux linked to the surface in unit of V-m is

  • EL2

  • EL2 cos θ

  • EL2 sin θ

  • EL2 sin θ

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115.

The electric field at a distance 3R/2 from the centre of a charged conducting spherical shell of radius R is E. The electric field at a distance R/2 from the centre of the sphere is

  • zero

  • E

  • E/2

  • E/2

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116.

The electric field of an electromagnetic wave in free space is given by stack bold E bold space with rightwards arrow on top space equals space 10 space cos space left parenthesis 10 to the power of 7 space straight t space space plus kx right parenthesis bold j with hat on top space straight V divided by straight m, where t and x are in seconds and meters respectively. It can be inferred that

1) the wavelength λ is 188.4 m.
2)The wave number k is 0.33 rad/m.
3)The wave amplitude is 10 V /m.
4)The wave is propagating along +x direction

  • (3) and (4)

  • (1) and (2) 

  • (2) and (3)

  • (2) and (3)

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117.

The electric potential at a point (x, y, Z) is given by

V = - x2y -xz3 + 4

The electric field E at that point is

  • bold E with bold rightwards arrow on top space equals bold i with bold hat on top space left parenthesis 2 space xy space plus space straight z cubed right parenthesis space plus space bold j with hat on top space straight x squared space plus space bold k with bold hat on top space 3 xz squared
  • bold E with bold rightwards arrow on top space equals bold i with bold hat on top space 2 space xy space plus space bold j with hat on top space left parenthesis straight x squared space plus straight y squared space right parenthesis space plus space bold k with bold hat on top space left parenthesis 3 xz space minus straight y squared right parenthesis
  • bold E with bold rightwards arrow on top space equals bold i with bold hat on top space left parenthesis straight z cubed right parenthesis space plus space bold j with hat on top space left parenthesis xyz space right parenthesis space plus space bold k with bold hat on top space straight z squared
  • bold E with bold rightwards arrow on top space equals bold i with bold hat on top space left parenthesis straight z cubed right parenthesis space plus space bold j with hat on top space left parenthesis xyz space right parenthesis space plus space bold k with bold hat on top space straight z squared


A.

bold E with bold rightwards arrow on top space equals bold i with bold hat on top space left parenthesis 2 space xy space plus space straight z cubed right parenthesis space plus space bold j with hat on top space straight x squared space plus space bold k with bold hat on top space 3 xz squared

The electric field at a point is equal to the negative gradient of the electrostatic potential at that point.

Potential gradient relates to electric field according to the following relation E = -dV/dr


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118.

A hollow cylinder has to charge q coloumb within it. Φ is the electric flux in a unit of voltmeter associated with the curved surface B, the flux linked with the plane surface A in a unit of voltmeter will be:

  • 1 half open parentheses q over epsilon subscript o minus capital phi close parentheses
  • fraction numerator straight q over denominator 2 straight epsilon subscript straight o end fraction
  • straight ϕ over 3
  • straight ϕ over 3
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119.

In a discharge tube ionization of enclosed gas is produced due to collisions between

  • positive ions and neutral atoms/molecules

  • negative electrons and neutral atoms/molecules

  • photons and neutral atoms/molecules

  • photons and neutral atoms/molecules

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120.

A square surface of side L m is in the plane of the paper. A uniform electric field straight E with rightwards arrow on top space left parenthesis straight V divided by straight m right parenthesis, also in the plane of the paper, is limited only to the lower half of the square surface, (see figure). The electric flux in SI units associated with the surface is

  • EL squared divided by left parenthesis 2 straight epsilon subscript 0 right parenthesis
  • EL squared divided by 2
  • zero

  • zero

614 Views

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