Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

Advertisement

151.

In a case of infinite long wire electric field is proportional to

  • 1r

  • 1r2

  • 1r3

  • r0


A.

1r

By using Gauss law and by solving we get this result 

Electric field due to the infinite long wire of linear charge density  λ  given by 

     E = λ2πε0 r

   

The above diagram is of the electric field generated by a uniformly charged wire.


Advertisement
152.

Assertion: In a cavity within a conductor, the electric field is zero.

Reason: Charges in a conductor reside only at its surface.

  • If both assertion and reason are true and reason is the correct explanation of assertion

  • If both assertion and reason are true but reason is not the correct explanation of assertion

  • If assertion is true but reason is false

  • If both assertion and reason are false


153.

Two parallel large thin metal sheets have equal surface charge densities ( σ = 26.4 × 10-12 C/m2 ) of opposite signs. The electric field between these sheets is

  • 1.5 N/C

  • 1.5 × 10-10 N/C

  • 3 N/C

  • 3 × 10-10 N/C 


154.

The spatial distribution of the electric field due to two charges (A, B) is shown in figure. Which one of the following statements is correct?

  • A is +ve and +B is -ve and A > B

  • A is -ve and B is +ve; A = B

  • both are +ve but A > B

  • both are -ve but A > B


Advertisement
155.

Using mass (M), length (L), time (T ) and current (A) as fundamental quantities, the dimension of permeability is

  • [ M-1 L T-2 A ]

  • [ M L2 T-2 A-1 ]

  • [ M L T-2A-2 ]

  • [ M L T-1 A-1 ]


156.

Length cannot be measure by

  • fermi

  • micron

  • debye

  • light year


157.

Two spheres of same metal have radii a and b. Thet have been connected to a conducting wire. Find the ratio of the electric field intensity upon them.

  • a/b

  • b/a

  • b2 / a

  • b2/a2


158.

Figure shows the electric lines of forces emerging from a charged body. If the electric field at A and B are EA and  EB respectively and if the displacement between A and B is r, then

    

  • EA > EB

  • EA < EB

  • EA = EB/r

  • EA = E/ r2


Advertisement
159.

Qεo

  • Q6εo

  • Q6 εo

  • Qεo a2

  • Q4πεoa2


160.

A small piece of metal wire is dragged across the gap between the pole pieces of a magnet in 0.4 sec. If magnetic flux between the pole pieces is known to be 8 × 10-4 Wb, then induced emf in the wire, is

  • 4 × 10-3 V

  • 8 × 10-3 V 

  • 20 × 10-3 V

  • 6 × 10-3 V


Advertisement