A Gaussian sphere encloses an electric dipole within it. The total flux across the sphere is
zero
half that due to a single charge
double that due to a single charge
dependent on the position of the dipole
The specific charge of a proton is 9.6 x107 C kg-1 The specific charge of an alpha particle will be
9.6 x107 C kg-1
19.2 x107 C kg-1
4.8 x107 C kg-1
2.4 x107 C kg-1
Point charges + 4q, - q and+ 4q are kept on the x-axis at points x = 0, x = a and x = 2a respectively, then
only- q is in stable equilibrium
all the charges are in stable equilibrium
all the charges are in unstable equilibrium
none of the above
If Ea be the electric field strength of a short dipole at a point on its axial line and Ee that on equilateral line at the same distance, then
Ee = 2Ea
Ea = 2Ee
Ea = Ee
none of these
Charges 4Q, q and Q are placed along x-axis at positions x = 0, x = l/2 and x = l, respectively. Find the value of q so that the force on charge Q is zero:
Q
-Q
Two small charged spheres A and B have charges 10 C and 40 C respectively and are held at a separation of 90 cm from each other. At what distance from A, the electric intensity would be zero?
22.5 cm
18 cm
36 cm
30 cm
A charged particle moves in an electric field from A to B, then from B to A :
If WAB > WBA, then the field is conservative
If WAB + WBA = 0, then the field is conservative
If WAB + WBA > 0, then the field is conservative
If WAB = WBA, then the field is conservative
What is the angle between the electric dipole moment and the electric field strength due to it on the equatorial line?
0°
90°
180°
None of these
Two spheres of radii R1 and R2 respectively are charged and joined by a wire. The ratio of the electric field of spheres is :
The figure shows three points A, B and C in a region of a uniform electric field . The line AB is perpendicular and BC is parallel to the field lines. Then which of the following holds good?
VA = VB = VC
VA = VB > VC
VA = VB < VC
VA > VB = VC
B.
VA = VB > VC
Electric lines of force flow from higher potential to lower potential so,
VA = VB > VC