The magnetic flux through a loop of resistance 10 Ω is

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 Multiple Choice QuestionsMultiple Choice Questions

141.

Lenz's law of electromagnetic induction corresponds to the

  • law of conservation of charge

  • law of conservation of energy

  • law of conservation of momentum

  • law of conservation of angular momentum


142.

The current through a coil of self-inductance L = 2mH is given by i = t2e-t at time t. How long it will take to make the emf zero ?

  • 1 s

  • 2 s

  • 3 s

  • 4 s


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143.

The magnetic flux through a loop of resistance 10 Ω is given by (ϕ=5t2 − 4t+ 1 Wb). How much current is induced in the loop after 0.2 s ?

  • 0.4 A

  • 0.2 A

  • 0.04 A

  • 0.02 A


B.

0.2 A

The flux is given by ϕ = 5t2 - 4t + 1. The emf induced in the resistance would be equal to 

      e = - dt = 10 t - 4

Thus, the current induced in the loop is equal to

     i = eR = - 10 t - 410at t = 0.2 s, we have i = - 10 × 0.2 - 410 = 210= 0.2 A


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144.

The magnetic flux linked with a coil satisfies the relation ϕ = 4t2 + 6t + 9  Wb, where t is the time in second. The emf induced in the coil at t = 2 s is

  • 22 V

  • 18 V

  • 16 V

  • 40 V


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145.

A coil of self-inductance L is connected in series with a bulb B and an AC source. Brightness of the bulb decreases when

  • frequency of the AC source is decreased

  • number of turns in the coil is reduced

  • a capacitance of reactance XC =XL is included in the same circuit

  • an iron rod is inserted in the coil


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