A body falls from a height h = 200 m. The ratio of distance travelled in each 2 sec, during t = 0 to t = 6 second of the journey is
1 : 4 : 9
1 : 2 : 4
1 : 3 : 5
1 : 2 : 3
A particle falls towards earth from infinity. Its velocity on reaching the earth would be:
infinity
zero
According to Kepler's law, the time period of a satellite varies with its radius are as:
T2 ∝ R3
T3 ∝ R2
Mass of a planet is 10 times that of earth and radius is 2 times that of earth. If at the earth, the escape velocity of a satellite is Ves(e), then escape. velocity at the planet is :
ves(e)
5ves(e)
2 ves(e)
10 ves(e)
A.
ves(e)
ves(e) = ------------------ (1)
ves=
Here: Mp = 10 Me, Rp = 2Re
ves(p) = -----------------(2)
From eqs (1) and (2),we have
ves(p) =
A rocket is accelerated with speed v= 2, near earth surface and then it moves upward. At far distance from the earth surface, the speed of the rocket will
be:
(2-)
A satellite is in a circular orbit round the earth at an altitude R above the earth's surface,where R is the radius of the earth. If g is the acceleration due to gravity on the surface of the earth the speed of the satellite is
Two satellites S1 and S2 revolve round a planet in coplanar circular orbits in the same sense. Their periods of revolution are 1 h and 8 h respectively. The radius of the orbit of S1 is 104 km. The speed of S2 relative to S1 when they are closest, in km/h is
104
2 × 104
104
4 × 104
If the height of a satellite from the earth is negligible in comparison to the radius of the earth R, the orbital velocity of the satellite is
gR
A satellite is revolving round the earth in an elliptical orbit. Its speed
will be same at all points of the orbit
will be maximum when it is at maximum distance from earth
will be maximum when its distance from the earth will be minimum
goes on increasing or decreasing continuous depending upon the mass of the satellite
A satellite of mass m, revolving round a planet of mass M in a circular orbit of radius r, then orbital velocity of the satellite is