A capillary tube of radius r can support a liquid of weight 6.28 x 10-4 N. If the surface tension of the liquid is 5 x 10-2N/m. The radius of capillary must be
m
1.5
The soap bubbles have radii in the ratio 2: 1 ratio of excess pressure in side there is
1:4
4:1
2:1
1:2
The radius R of the soap bubble is doubled under isothermal condition. If T be the surface tension of soap bubble. The work done in doing so is given by
An ice-cube of density 900 kg /m3 is floating in water of density 1000 kg / m3. The percentage of volume of ice-cube outside the water is
20%
35%
10%
25%
A tank is filled with water upto height H. When a hole is made at a distance h below the level of water. What will be the horizontal range of water jet?
A charged oil drop is suspended in uniform field of 3 x 104 V/m so that it neither falls nor rises. The charge on the drop will be (Take the mass of the charge = 9.9 x 10-15 kg and g = 10 m/s2 )
3.3 × 10-18 C
3.2 × 10-18 C
1.6 × 10-18 C
4.8 × 10-18 C
A frame made of metallic wire enclosing a surface area A is covered with a soap film. If the area of the frame of metallic wire is reduced by 50%, the energy of the soap film will be changed by
100%
75%
50%
25%
The potential energy of a molecule on the surface of a liquid compared to one inside the liquid is
zero
lesser
equal
greater
Aerofils are so designed that the speed of air
on top side is more than on lower side
on top side is less than on lower side
is same on both sides
is turbulent
Two glass plates are separated by water. If surface ension of water is 75 dyne/cm and area of each plate wetted by water is 8 cm2 and the distance between the plates is 0.12 mm, then the force applied to separate the two plates is
102 dyne
104 dyne
105 dyne
106 dyne
C.
105 dyne
The shape of water layer between the two plates is shown in figure
Thickness d of the film = 0.12 mm
= 0.012 cm
Radius R of the cylindrical face = d/2
Pressure difference across the surface
= T/R
= 2T/d
Area of each plate wetted by water = A
Force F required to separate the two plates is given by
F = pressure difference × area
=
Putting the given values, we get
F =
F = 105 dyne