The speed of the projectile at its maximum height is half of its initial speed. The angle of projection is
60o
15o
30o
30o
A particle moves in the x-y plane according to rule x = a sin ωt and y = a cos ωt. The particle follows
an elliptical path
a circular path
a parabolic path
a parabolic path
A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 s is s1 and that covered in the first 20 s is s2, then
s2 = 2s1
s2 = 3s1
s2 = 4 s1
s2 = 4 s1
Two bodies of mass 1 kg have position vectors, respectively.The centre of mass of this system has a position vector
B.
The position vector of centre of mass
Point to know:
The centre of mass changes its position only under the translatory motion. There is no effect of rotatory motion on centre of mass of the body.
If is the force acting on a particle having position vector be the the torque of this force about the origin, then
The distance travelled by a particle starting from rest and moving with an acceleration 4/3 ms-2 in the third second is
6 m
4 m
10/3
10/3
A particle shows distance -time curve as given in this figure. The maximum instantaneous velocity of the particle is around the point
B
C
D
D
A particle moves in a straight line with a constant acceleration. It changes its velocity from 10 ms-1 to 20 ms-1 while passing through a distance 135 m in t second. The value of t is
10
1.8
12
12
A particle of mass is projected with the velocity v making an angle of 45o with the horizontal.
When the particle lands on the level ground the magnitude of the change in its momentum will be
2 mv
The position x of a particle with respect to time t along x- axis is given by x = 9t2 -t3 where x is in meter and t in second. What will be the position of this particle when it achieves maximum speed along the +x direction?
32 m
54 m
81 m
81 m