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 Multiple Choice QuestionsMultiple Choice Questions

291.

Which one of the following is used as a moderator in nuclear reaction?

  • Uranium

  • Heavy water

  • Cadmium

  • Plutonium


292.

The Kα line from molybdenum (atomic number = 42) has a wavelength of 0.7078 A. The wavelength of Kα line of zinc (atomic number = 30) will be

  • A

  • 1.3872 A

  • 0.3541 A

  • 0.5 A


293.

Decay constant of radioactive element is 1.5 × 10-9/s. Average age of element is

  • 1.5 × 109

  • 4.62 × 108

  • 6.67 × 108

  • 10.35 × 108


294.

Half-life of radium is 1600 yr, then its 1/16th part will remain undecayed after

  • 1200 yr

  • 6400 yr

  • 1800 yr

  • 2200 yr


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295.

Atomic number of an atom is Z and mass number is m, then number of neutrons in its nucleus is

  • m − Z

  • mZ

  • m + Z

  • m × Z


296.

Nucleus of an atom has

  • e and n

  • e and p

  • p and n

  • e, p and n


297.

A nucleus undergoes β-decay. The mass number and  atomic number change as

  • mass number and atomic number both increases

  • mass number remain same and atomic number increases

  • mass number increases and atomic number remain same

  • mass number and atomic number both decreases


298.

When a radioactive isotope Ra22888 decay in series by the emission of 3α -particles and a β -particle, the isotope finally formed is

  • X21682

  • X21583

  • X21688

  • X21683


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299.

The activity of a radioactive element decreases to one third of the original activity I0 , in a period of 9 years. After a further lapse of 9 years, its activity will be

  • I0

  • (2/3) I0

  • I0 / 9

  • I0 / 6


C.

I0 / 9

Activity A of a radioactive is defined as its disintegration rate.

i.e.            A = − (dN/dt)

                   = N − N0e-λt

          -dNdt = λN0e-λt = λN

∴              A = λN

Hence,   AA0 = λNλN = NN0

Fraction value period t, is the time after which the number of mother nuclei left is a fraction times than at start. Then, after a lapse of time t(= ntf ) the number of surviving mother nuclei is given by

          NN0 = fnf  or A A0 = fnf

Here,   A0 = I0 and tf = 9 years

             t = 9 + 9 = 18 years

            nf = t / tf = 18 / 9 = 2

Now,      f = (1/3)

∴           AA0 = 132 = 19 or A = I09


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300.

If Mo is the mass of an oxygen isotope O178, Mp and Mn are the masses of a proton and a neutron, respectively, the nuclear binding energy of the isotope is

  • (Mo − 8Mp) c2

  • (Mo − 8Mp − 9Mn) c2

  • Moc2

  • (Mo − 17Mn) c2


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